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Marat540 [252]
3 years ago
5

Can you help me real quick guys?

Mathematics
1 answer:
Allisa [31]3 years ago
8 0

Answer:

1

hope it's helpful ❤❤

THANK YOU

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a company’s stock was selling at $24 a share a month later it was selling at $30 a share what is the percent gain
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Mmm like 4 if to 30 in total but I ain’t know out 100
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When rabbits were introduced to the continent of Australia they quickly multiplied and spread across the continent since there w
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Answer:

a. y=6(1.7472)^x

b. y=6e^{0.558t}

c.13.3 months

Step-by-step explanation:

a.-Given the first term  at t_0 is 6 and the second term at t_3 is 32.

-Let's take rabbit population as a function of time to be

y=ab^x

where y is the population at time x and a the initial population at t_0\\

#We substitute our values to calculate the value of the constant b:

y_x=ab^x\\\\y_3=ab^3\\\\32=6b^3\\\\b=1.472

#Replace b in the population function:

y=ab^x, b=1.7472,a=6\\\\\therefore y=6(1.7472)^x

Hence, the regression for the rabbit population as a function of time x is y=6(1.7472)^x

b. The exponential function in terms of base e is usually expressed as:

A=A_0e^{kt}

Where:

A_0-is the initial population at t_o

A-is the population at time t.

k-is the  exponential growth constant.

e- the exponent

Our function in terms of base exponent is rewritten as:

y=A_0e^{kt}

#Substitute with actual figures to solve for t:

y=A_0e^{kt}, y=32, xt=3, A_0=6\\\\32=6e^{3k}\\\\3k=In (32/6)\\\\k=0.5580

Hence, the regression equation in terms of base e is y=6e^{0.558t}

c. We substitute y with any number higher than 10,000 to estimate the time for the rabbits to exceed 10,000.

-We know that y=6e^{0.558t}.

Therefore we calculate t as(take y=10001):

y=6e^{0.558t}, y=10001\\\\10001=6e^{0.558t}\\\\1666.8333=e^{0.558t}\\\\0.558t= In 1666.8333\\\\t=13.2951

Hence, it takes approximately 13.3 months for the population to exceed 10000

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4 years ago
6) Janelle has 150 surveys she has to hand out. She conducts 11 surveys
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Answer:

y = 150 - 11x

Step-by-step explanation:

Janelle is starting out with 150 surveys and if she is conducting 11 surveys an hour, then that means you need to subtract 11x from 150 because that will give you how many surveys she has left.

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How do you add (−3c 4 −5c 2 −7c)+(4c 4 +8c 3 +2c 2 )
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I add awl them up or subtract which one i have to do that the one wiil do
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