Answer:
2144.66 cubic inches
Step-by-step explanation:
The fishbowl is shaped like a sphere the fishbowl has a diameter of 16.
What is the closest value of water in the Fishbowl in cubic inches?
From the any question, we were told to find the closest value of the water in the fishbowl in cubic inches.
This means we are to find the volume.
The volume of a sphere is given as:
4/3πr³
We are given Diameter of the fish bowl = 16 inches
Radius = Diameter/2 = 16 inches/2
= 8 inches
Hence,
Volume of the sphere (Volume of water) = 4/3 × π × 8³
= 2144.66 cubic inches
I believe the answer is C :)
Answer:
Width = 18 inches
Length = 59 inches
Step-by-step explanation:
The length of a rectangle is five more than triple the width. If the perimeter is 154 inches, what are the dimensions
Perimeter of a rectangle = 2L + 2W
The length of a rectangle is five more than triple the width.
L = Length = 5 + 3W
W = Width
If the perimeter is 154 inches, what are the dimensions
Hence,
154 = 2L + 2W
154 = 2(5 + 3W ) + 2W
154 = 10 + 6W + 2W
Collect like terms
154 - 10 = 8W
144 = 8W
W = 144/8
W = 18 inches
Length = 5 + 3W
Length = 5 + 3(18)
Length = 5 + 54
Length = 59 inches
Answer:
(y + 1) = 3( x +2)
Step-by-step explanation:
from equation,
y - y1 = m( x - x1)
given x1=2, y1= -1
m = 3 (slope)
substitute
y - (-1) = 3( x - 2)
ans: y+1= 3(x+2)
Answer:
A.
Step-by-step explanation:
