Answer:
70000 gallons
Step-by-step explanation:
The total time between 8 a.m. to 6 p.m is 10 hours. The company starts producing at 8 am, therefore the time from 8 am to noon (that is 12 p.m) is 4 hours.
Since clients demand 100,000 gallons of milk over the course of one day, the demand of milk per hour = total demand per day/ total time per day
Demand per hour = 100000 gallons / 10 hours = 10000 gallons per hour
Since the milk is processed at a fixed rate of 7500 gallons/hour, At noon the amount of of milk produced = 7500 gallons/hour × 4 hours = 30000 gallons.
The gallons of milk are in the queue to be processed at noon = 100000 gallons - 30000 gallons = 70000 gallons
Since, the number w and 0.8 are additive inverses.
A number 'a' is said to have an additive inverse '-a' if "a+ (-a)= 0".
Since, 'w' and '0.8' are additive inverses of each other such that 
Therefore, the value of 'w' should be '-0.8' so that 
.
So, the value of 'w' is =0.8
Now, Refer to the attached image which represents the position of 0.8 , w ( that is -0.8) and the sum of 0.8 and w.
Sum of 0.8 and w = 0.8 + w
= 0.8 +(-0.8)
= 0.
Answer:
w>3
Step-by-step explanation:
Answer:
x=$10
y=$12
Step-by-step explanation:
Step one:
given
let senior tickets be x
and child be y
8x+9y=188----1
also on the second day
x+5y=70-------2
the system of equation is
8x+9y=188-----1
x+5y=70---------2
x=70-5y, put this in 1
8(70-5y)+9y=188
560-40y+9y=188
-31y=-372
divide by -31
y=-372/-31
y=$12
put y= 12 in x+5y=70---------2
x+5(12)=70---------2
x+60=70
x=$10
