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a_sh-v [17]
3 years ago
10

30 POINTS A student answered the question, 3 1/2 ÷ 5 4/9. He got the answer 15 9/8. What did he do wrong.

Mathematics
1 answer:
AleksAgata [21]3 years ago
4 0

Answer:

He multiplied the whole numbers and  divided the fractions

Step-by-step explanation:

3 1/2 ÷ 5 4/9

change the mixed numbers to improper fractions

3 1/2 = (2*3 +1)/2 =7/2

5 4/9 = (9*5+4)/9 =49/9

7/2 ÷ 49/9

copy dot flip

7/2 * 9/49

rewrite

7/49 * 9/2

1/7 * 9/2

9/14

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Tan(2 sin^-1 0.4)<br> Find the Exact value
stiv31 [10]

Answer:

tan(2u)=[4sqrt(21)]/[17]

Step-by-step explanation:

Let u=arcsin(0.4)

tan(2u)=sin(2u)/cos(2u)

tan(2u)=[2sin(u)cos(u)]/[cos^2(u)-sin^2(u)]

If u=arcsin(0.4), then sin(u)=0.4

By the Pythagorean Identity, cos^2(u)+sin^2(u)=1, we have cos^2(u)=1-sin^2(u)=1-(0.4)^2=1-0.16=0.84.

This also implies cos(u)=sqrt(0.84) since cosine is positive.

Plug in values:

tan(2u)=[2(0.4)(sqrt(0.84)]/[0.84-0.16]

tan(2u)=[2(0.4)(sqrt(0.84)]/[0.68]

tan(2u)=[(0.4)(sqrt(0.84)]/[0.34]

tan(2u)=[(40)(sqrt(0.84)]/[34]

tan(2u)=[(20)(sqrt(0.84)]/[17]

Note:

0.84=0.04(21)

So the principal square root of 0.04 is 0.2

Sqrt(0.84)=0.2sqrt(21).

tan(2u)=[(20)(0.2)(sqrt(21)]/[17]

tan(2u)=[(20)(2)sqrt(21)]/[170]

tan(2u)=[(2)(2)sqrt(21)]/[17]

tan(2u)=[4sqrt(21)]/[17]

7 0
3 years ago
What is the total weekly pay for a person earning $9.00 an hour and working only 8 hours a day for 5 days?
melomori [17]
First you woyld find how many hours total he worked.
5 \times 8 = 40
Then take the number of hours and multiply by the pay earned per hour.
40 \times 9 = 360
They would make $360 per week.
6 0
3 years ago
Find the common difference of the arithmetic<br> sequence 4, 10, 16,
DIA [1.3K]

Answer:

10it is 10

Step-by-step explanation:

7 0
2 years ago
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IRINA_888 [86]

Answer:

It’s either A or C

Step-by-step explanation:

3 0
3 years ago
Read 2 more answers
What is the horizontal asymptote for y(t) for the differential equation dy dt equals the product of 2 times y and the quantity 1
marta [7]
First, we need to solve the differential equation.
\frac{d}{dt}\left(y\right)=2y\left(1-\frac{y}{8}\right)
This a separable ODE. We can rewrite it like this:
-\frac{4}{y^2-8y}{dy}=dt
Now we integrate both sides.
\int \:-\frac{4}{y^2-8y}dy=\int \:dt
We get:
\frac{1}{2}\ln \left|\frac{y-4}{4}+1\right|-\frac{1}{2}\ln \left|\frac{y-4}{4}-1\right|=t+c_1
When we solve for y we get our solution:
y=\frac{8e^{c_1+2t}}{e^{c_1+2t}-1}
To find out if we have any horizontal asymptotes we must find the limits as x goes to infinity and minus infinity. 
It is easy to see that when x goes to minus infinity our function goes to zero.
When x goes to plus infinity we have the following:
$$\lim_{x\to\infty} f(x)$$=y=\frac{8e^{c_1+\infty}}{e^{c_1+\infty}-1} = 8
When you are calculating limits like this you always look at the fastest growing function in denominator and numerator and then act like they are constants. 
So our asymptote is at y=8.

3 0
3 years ago
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