Answer:
10 and 12
Step-by-step explanation:
let the consecutive even integers be n and n + 2 , then
n² - 64 = 3(n + 2) ← distribute parenthesis
n² - 64 = 3n + 6 ( subtract 3n + 6 from both sides )
n² - 3n - 70 = 0 ← in standard form
(n - 10)(n + 7) = 0 ← in factored form
Equate each factor to zero and solve for n
n - 10 = 0 ⇒ n = 10
n + 7 = 0 ⇒ n = - 7
Since n must be a positive even integer then n = 10 and n + 2 = 10 + 2 = 12
The 2 numbers are 10 and 12
Answer: 40 coins. Doesn't your profile say college?
Answer:
40
Step-by-step explanation:
The first box is 2--> 16*3 divided by 24= 2
Second box is 40--> 5*24 divided by 3= 40
Hope it helps.
Answer:
8x - 12y
Step-by-step explanation:
4(2x-3y)
Distribute/multiply the 4 to everything in the parentheses
4 * 2x = 8x 4 * -3y = -12y
8x - 12y
