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oee [108]
3 years ago
9

if the area of a rectangle is expressed as x^4 - 9y^2, then the product of the length and the width of the rectangle could be ex

pressed as...
Mathematics
1 answer:
kvasek [131]3 years ago
6 0

Answer:the product of the length and the width of the rectangle could be expressed as

(x^2 - 3y)(x^2 + 3y)

Step-by-step explanation:

If the area of a rectangle is expressed as x^4 - 9y^2, we would determine the dimensions by simplifying the given expression. The simplified expression becomes

(x^2 - 3y)(x^2 + 3y)

Let us check by multiplying each term in one parenthesis by each term in the other parenthesis to get the given expression. It becomes

(x^2 - 3y)(x^2 + 3y) = x^4 + 3x^2y - 3x^2y - 9y^2 = x^4 - 9y^2

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At the bottom is a completed addition problem, with all the digits replaced by letters. Every letter represents a single digit a
Rashid [163]

Answer:

T = 5 (H = 7, M = 1); T = 7 (H = 4, M = 2); T = 9 (H = 1, M = 3)

Step-by-step explanation:

We know MH+MH+MH=TM

MH is a two digit number, and TM is also a two digit number.

MH+MH+MH=3*(MH)<100

3M<=9, meaning that M could be 1, 2, or 3.

If M=1, MH+MH+MH=3(10+H)=30+3H=TM=10*T+1

30+3H=10T+1, so 3H must include 1 in one's digit.

The only possibility is that 3H = 21, then H = 7

MH+MH+MH=17+17+17=TM=51, T = 5

If M=2, MH+MH+MH=3(20+H)=60+3H=TM=10T+2

60+3H=10T+2, so 3H must include 2 in one's digit.

The only possibility is 3H = 12, then H = 4

MH+MH+MH=24+24+24=72, T = 7

If M=3, MH+MH+MH=3(30+H)=90+3H=TM=10T+3

90+3H=10T+3, so 3H must include 3 in one's digit.

The only possibility is 3H = 3, then H =1

MH+MH+MH=31+31+31=93, T=9

4 0
3 years ago
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Step-by-step explanation:

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Step-by-step explanation:

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