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elena55 [62]
3 years ago
5

If 1 candy cost 20$ what is the amount of 30 candy​

Mathematics
2 answers:
lana [24]3 years ago
5 0

Answer:

$600

Step-by-step explanation:

you would do 30 x 20 since each piece of candy cost $20.

BigorU [14]3 years ago
3 0
30 candies would cost 600 dollars. you take 30 * 20 :)
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The railroad company wants to sell $8,134 in tickets. If each ticket costs $7, how many
Licemer1 [7]

Answer:

1162 tickets will need to be sold

Step-by-step explanation:

8134 / 7 = 1,162

8 0
2 years ago
A sine function is transformed such that it has a single x-intercept in the interval (0,pi), a period of pi and a y-intercept of
Alex787 [66]
Just to make sure we're using the same language, I'm going to use the function form of:

y = A\sin(kx) + h

[] I would agree that k = 2, since the period is only half as long as a normal sine function. So, we so far, have y = A sin(2x) + h. We still need to find A and h.

[] The y-intercept is 3. Remember that the y-intercept happens when x = 0. So, plugging in x = 0 into our formula, we have: 3 = A sin(2*0) + h. In other words, 3 = A sin(0) + h = 0 + h = h. So, we now know that h = 3. The formula is now y = A sin(2x) + 3.

[] Finally, there is a single x-intercept. Picture what the sine function looks like right now, it is floating in the air around y = 3. We need to stretch it vertically until it just grazes the x-axis. 

If A = 1, then our sine function bounces between 2 and 4 (+/- 1 around h = 3). But that doesn't touch 0, so no good.

If A = 2, then our sine function bounces between 1 and 5 (+/- 2 around h = 3). Again, not quite touching 0 yet.

The answer should be A = 3, then our sine function bounces between 0 and 6 (+/- 3 around h = 3).

The final formula is y = 3 sin(2x) + 3.
7 0
3 years ago
Show that (0, 0) is equidistant from (1, 2), (-1, -2) and (2, 1).​
Len [333]

Step-by-step explanation:

1) if (0;0) if point A, (1;2) is point B; (-1;-2) is C, (2;1) is D, then

2) the vector AB is (1;2); vector AC is (-1;-2) and vector AD is (2;1), then

3) the length of AB, AC and AD are:

|AB|=\sqrt{1^2+2^2}=\sqrt{5};

|AC|=\sqrt{(-1)^2+(-2)^2}=\sqrt{5};

|AD|=\sqrt{2^2+1^2}=\sqrt{5}.

4) if the lengths above are equal, then it means that (0, 0) is equidistant from (1, 2), (-1, -2) and (2, 1).

3 0
2 years ago
How do you do these questions?
Doss [256]

Step-by-step explanation:

(a) Fₙ₋₁ > 0, so Fₙ₊₁ > Fₙ.  Each term is bigger than the one before it, so the function is increasing, meaning the series will diverge to infinity.

(b) Fₙ₊₁ / Fₙ = (Fₙ + Fₙ₋₁) / Fₙ

Divide.

Fₙ₊₁ / Fₙ = 1 + (Fₙ₋₁ / Fₙ)

Rewrite the second fraction using negative exponent.

Fₙ₊₁ / Fₙ = 1 + (Fₙ / Fₙ₋₁)⁻¹

Take the limit of both sides as n approaches infinity.

lim(n→∞) Fₙ₊₁ / Fₙ = 1 + lim(n→∞) (Fₙ / Fₙ₋₁)⁻¹

Substitute with φ.

φ = 1 + φ⁻¹

Solve.

φ² = φ + 1

φ² − φ − 1 = 0

φ = [ -(-1) ± √((-1)² − 4(1)(-1)) ] / 2(1)

φ = (1 ± √5) / 2

Since the ratio can't be negative:

φ = (1 + √5) / 2

4 0
3 years ago
Came across this question on my home work can some one please show how to sketch it correctly?
kap26 [50]

Answer:

Step-by-step explanation:

8 0
1 year ago
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