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s2008m [1.1K]
3 years ago
13

Simplify. 2+35x−1−15x 1+25x 3−45x 1−25x 3+25x

Mathematics
2 answers:
Ksenya-84 [330]3 years ago
5 0

Answer:

1 + 2/5x

Step-by-step explanation:

2+3/5x−1−1/5x

Combine like terms

2-1   + 3/5x-1/5x

1 + 2/5x

Lelu [443]3 years ago
3 0

Answer:

Option A is correct.

1+\frac{2}{5}x

Step-by-step explanation:

Simplify: 2+\frac{3}{5}x - 1 -\frac{1}{5}x                ......[1]

Like terms are those terms who have same variable to the same power.

Combine like terms in [1] ,we have;

1+(\frac{3}{5}x- \frac{1}{5}x)

Simplify:

1+\frac{2}{5}x

Therefore, the simplified form of  2+\frac{3}{5}x - 1 -\frac{1}{5}x  is, 1+\frac{2}{5}x

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Dalia saved $3000 last year. She said $600 in the month of January. What percent of the total amount of money she saved last yea
Anni [7]
1. We assume, that the number 3000 is 100% - because it's the output value of the task. 
<span>2. We assume, that x is the value we are looking for. </span>
<span>3. If 100% equals 3000, so we can write it down as 100%=3000. </span>
<span>4. We know, that x% equals 600 of the output value, so we can write it down as x%=600. </span>
5. Now we have two simple equations:
1) 100%=3000
2) x%=600
where left sides of both of them have the same units, and both right sides have the same units, so we can do something like that:
100%/x%=3000/600
6. Now we just have to solve the simple equation, and we will get the solution we are looking for.

7. Solution for 600 is what percent of 3000

100%/x%=3000/600
<span>(100/x)*x=(3000/600)*x       - </span>we multiply both sides of the equation by x
<span>100=5*x       - </span>we divide both sides of the equation by (5) to get x
<span>100/5=x </span>
<span>20=x </span>
<span>x=20
So 600 is 20% of 3000</span>
7 0
3 years ago
Write the next three terms of the geometric sequence.
Sati [7]

Answer:

5, 1, 0.2

Step-by-step explanation:

Divide the number by 5 to get the next one.

8 0
3 years ago
PLEASE HELP!! WILL GIVE BRAINLIEST!!
Anestetic [448]
Area of part 1:A1=base*height/2=(8+2)*(8-2-2-1)/2=10*3/2=15 ft^2Area of part 2:A2=length*width=(8+2)*1=10 ft2Area of part 3:A3=length*width=8*2=16 ft2
Total shaded area : A1+A2+A3=41 ft2Total area of the reactangle : A=16*8=128 ft2Total area of the nonshaded region : 128-41=87 ft2

8 0
3 years ago
Which equation has the solutions x=1+or-square root of 5?
stiv31 [10]

We will proceed to solve each case to determine the solution of the problem.

<u>case a)</u> x^{2}+2x+4=0

Group terms that contain the same variable, and move the constant to the opposite side of the equation

x^{2}+2x=-4

Complete the square. Remember to balance the equation by adding the same constants to each side.

x^{2}+2x+1=-4+1

x^{2}+2x+1=-3

Rewrite as perfect squares

(x+1)^{2}=-3

(x+1)=(+/-)\sqrt{-3}\\(x+1)=(+/-)\sqrt{3}i\\x=-1(+/-)\sqrt{3}i

therefore

case a) is not the solution of the problem

<u>case b)</u> x^{2}-2x+4=0

Group terms that contain the same variable, and move the constant to the opposite side of the equation

x^{2}-2x=-4

Complete the square. Remember to balance the equation by adding the same constants to each side.

x^{2}-2x+1=-4+1

x^{2}-2x+1=-3

Rewrite as perfect squares

(x-1)^{2}=-3

(x-1)=(+/-)\sqrt{-3}\\(x-1)=(+/-)\sqrt{3}i\\x=1(+/-)\sqrt{3}i

therefore

case b) is not the solution of the problem

<u>case c)</u> x^{2}+2x-4=0

Group terms that contain the same variable, and move the constant to the opposite side of the equation

x^{2}+2x=4

Complete the square. Remember to balance the equation by adding the same constants to each side.

x^{2}+2x+1=4+1

x^{2}+2x+1=5

Rewrite as perfect squares

(x+1)^{2}=5

(x+1)=(+/-)\sqrt{5}\\x=-1(+/-)\sqrt{5}

therefore

case c) is not the solution of the problem

<u>case d)</u> x^{2}-2x-4=0

Group terms that contain the same variable, and move the constant to the opposite side of the equation

x^{2}-2x=4

Complete the square. Remember to balance the equation by adding the same constants to each side.

x^{2}-2x+1=4+1

x^{2}-2x+1=5

Rewrite as perfect squares

(x-1)^{2}=5

(x-1)=(+/-)\sqrt{5}\\x=1(+/-)\sqrt{5}

therefore

case d) is the solution of the problem

therefore

<u>the answer is</u>

x^{2}-2x-4=0

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