Answer:
27720
Step-by-step explanation:
Given that there are 12 students in a graduate class. The students are to be divided into three groups of 3, 4, and 5 members for a class project.
From 12 students 3 students for group I can be selected in 12C3 ways.
Now from remaining 9, 4 students can be selected for II group in 9C4 ways
The remaining 5 have to be placed in III group.
Hence possible divisions for grouping the 12 students in the class into three groups
= 12C3 *9C4
=
Answer:
1. ridescost+admission=total
if x=number of tickets and y is total and cost per ride is 1.25 then
1.25x+admission=y
if we solve
when x=25, y=43.75
1.25(25)+admission=43.75
31.25+admission=43.75
minus 31.25 from both sides
admission=12.50
a.
y=1.25x+12.5
b.
x is number of tickets and y is total cost
c. math, seriously, just read what is above option a (the one in the top of the answer)
if you're too lazy then:
ridescost+admission=total
if x=number of tickets and y is total and cost per ride is 1.25 then
1.25x+admission=y
if we solve
when x=25, y=43.75
2.
(a)
m = (y2 - y1) / (x2 - x1) = (4 - 9)/(-2 - 8) = -5/(-10) = 1/2
(b)
y - y1 = m(x - x1)
Using the first given point,
y - 9 = (1/2)(x - 8)
Using the second given point,
y - 4 = (1/2)(x + 2)
note they both simplify to
y = (1/2)x + 5
(c)
y = (1/2)x + 5
3.
