Required expression is x/9 - 7
Given: 3y cos x = x² + y²
Define

Then by implicit differentiation, obtain
3y' cos(x) - 3y sin(x) = 2x + 2y y'
y' [3 cos(x) - 2y] = 2x + 3y sinx)
Answer:
Answer:
(1.2, –4.7)
Step-by-step explanation:
Since in the question it is mentioned that on the plane of coordinate, a line is made from point A (7,-2) to point B(-8,-9)
Also, the ratio of A to B is 5:8
Based on this, the x and y coordinates at point C is
![= [\frac{5\times (-8) + 8\times 7}{5 + 8} , \frac{5\times (-9) + 8\times -2}{5 + 8}]\\\\= [\frac{16}{3}, \frac{-61}{13}]](https://tex.z-dn.net/?f=%3D%20%5B%5Cfrac%7B5%5Ctimes%20%28-8%29%20%2B%208%5Ctimes%207%7D%7B5%20%2B%208%7D%20%2C%20%5Cfrac%7B5%5Ctimes%20%28-9%29%20%2B%208%5Ctimes%20-2%7D%7B5%20%2B%208%7D%5D%5C%5C%5C%5C%3D%20%5B%5Cfrac%7B16%7D%7B3%7D%2C%20%5Cfrac%7B-61%7D%7B13%7D%5D)
= (1.2, –4.7)
Hence, the x and y coordinates of point C is (1.2, –4.7)
Therefore the last option is correct
Answer:
z=2
Step-by-step explanation:
5/20=z/8
Rewrite the equation as z/8=5/20
z/8=5/20
Multiply both sides of the equation by 8.
8⋅z8=8⋅520
Simplify both sides of the equation.
z=2
Hope this helps! Plz mark as brainliest! :)