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Damm [24]
2 years ago
12

Henry has a bag containing 39 letter tiles, some consonants, and some vowels. He selects a tile without looking and then replace

s it. If he pulls 7 consonant tiles and 6 vowel tiles, which is the most likely number of consonant tiles in Henry's bag?
Mathematics
1 answer:
adoni [48]2 years ago
4 0

Answer:

21 consonant tiles

Step-by-step explanation:

Henry has a bag containing 39 letter tiles, some consonants, and some vowels.

He selects a tile without looking and then replaces it. If he pulls 7 consonant tiles and 6 vowel tiles, which is the most likely number of consonant tiles in Henry's bag?

Step 1

We add up the number of tiles that he pulls out of the bag

= 7 consonant tiles + 6 vowel tiles

= 13 tiles

Step 2

We divide the total number of tiles in the bag by the total number of tiles that was pulled out of the bag

= 39 tiles ÷ 13 tiles

= 3

Step 3

The most likely number of consonant tiles in Henry's bag is calculated as:

3 × The number of consonant tiles that was pulled out of the bag.

Hence:

3 × 7 consonant tiles

= 21 consonant tiles.

Therefore, the most likely number of consonant tiles in Henry's bag is 21 consonant tiles.

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Encuentre el radio y el área de círculos cuya circunferencias tienen las siguientes medidas
Vadim26 [7]

Answer:

Los radios de los círculos son r_{1} \approx 9.995, r_{2} \approx 2.013, r_{3} \approx 7.592, respectivamente.

Las áreas de los círculos son A_{1} \approx 313.845, A_{2} \approx 12.730, A_{3} \approx 181.077, respectivamente.

Step-by-step explanation:

La circunferencia (s) se calcula mediante la siguiente fórmula:

s = 2\pi\cdot r (1)

Donde r es el radio del círculo.

Una vez hallado el radio, se determina el área de la figura geométrica (A) mediante la siguiente fórmula:

A = \pi\cdot r^{2} (2)

Si conocemos que las circunferencias son s_{1} = 62.8, s_{2} = 12.65 y s_{3} = 47.7, respectivamente:

1) Radios de los círculos

r_{1} = \frac{s_{1}}{2\pi}, r_{2} = \frac{s_{2}}{2\pi}, r_{3} = \frac{s_{3}}{2\pi}

r_{1} \approx 9.995, r_{2} \approx 2.013, r_{3} \approx 7.592

2) Áreas de los círculos

A_{1} = \pi\cdot r_{1}^{2}, A_{2} = \pi\cdot r_{2}^{2}, A_{3} = \pi\cdot r_{3}^{2}

A_{1} \approx 313.845, A_{2} \approx 12.730, A_{3} \approx 181.077

6 0
3 years ago
If tomatoes are $3.22 per pound and Nico spends $5.76 on tomatoes, how many pounds did he purchase?
juin [17]

In order to find out the amount of pounds of tomatoes purchased:

  • We have to know how much one pound is ($3.22 per pound)

  • Total Nico spent ÷ Price per pound

    So it would be

  • 5.76 ÷ 3.22 = 1.78881987578

Rounding our decimal number:

  • If we round to our nearest tenths it would now be 1.8

Answer:

Therefore, the total number of pounds Nico purchased for $5.76 is 1.8lb.

4 0
2 years ago
E. Rebecca's goal is to average 86 on all of her tests. What will her score have to be on her next test to
Alik [6]

Step-by-step explanation:

How much test is she doing?

I think the question is missing something.

5 0
3 years ago
Suppose the time that it takes a certain large bank to approve a home loan is Normally distributed with mean (in days) μ and sta
kolezko [41]

Answer:

(c) H0 should be rejected

Step-by-step explanation:

Null hypothesis (H0): population mean is equal to 5

Alternate hypothesis (Ha): population mean is greater than 5

Z = (sample mean - population mean) ÷ (sd/√n)

sample mean = 5.3, population mean = 5, sd = 1, n = 500

Z = (5.3 - 5) ÷ (1/√500) = 0.3 ÷ 0.045 = 6.67

Using the normal distribution table, for a one tailed test at 0.01 significance level, the critical value is 2.326

Conclusion:

Since 6.67 is greater than 2.326, reject the null hypothesis (H0)

4 0
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after 1 year on the job M got a raise from $10.50 to $11.13 per our. What was the percent increase of her hourly wage
N76 [4]
The answer is 6% increase

6 0
3 years ago
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