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denis23 [38]
2 years ago
15

A secant and a tangent to a circle intersect in a 42-degree angle. The two arcs of the circle intercepted by the secant and the

tangent have measures in a 7:3 ratio. Find the measure of the third arc
Mathematics
1 answer:
Amanda [17]2 years ago
3 0

Answer:

The measure of the third arc is 150\°

Step-by-step  explanation:

step 1

we know that

The measurement of the external angle is the semi-difference of the arcs which comprises

in this problem

Let

x----> the greater arc of the circle intercepted by the secant and the tangent

y----> the smaller arc of the circle intercepted by the secant and the tangent

42\°=\frac{1}{2}(x-y)

84\°=(x-y) ----> equation A

\frac{x}{y}=\frac{7}{3}

x=\frac{7}{3}y -----> equation B

Substitute equation B in equation A and solve for y

84\°=(\frac{7}{3}y-y)

84\°=(\frac{4}{3}y)

y=3*84\°/4=63\°

Find the value of x

x=\frac{7}{3}(63\°)=147\°

step 2

Find the measure of the third arc

Let

z------> the measure of the third arc

we know that

x+y+z=360\° -----> complete circle

substitute the values and solve for z

147\°+63\°+z=360\°

z=360\°-(147\°+63\°)=150\°

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2 years ago
Store A
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<h3>Answer: Choice C) $1,444.50</h3>

========================================================

There are two methods to get the answer.

The slightly longer method is to take 7% of the original price to get

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A shortcut is to multiply the original price by 1.07

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4 0
3 years ago
10 POINTS!!! FULL ANSWER WITH FULL STEP BY STEP SOLUTION PLEASE. DO BOTH PARTS OF 1 AND ALL OF 2.
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One A
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to find b we use y= e^x ln(x)

e^x ln(x) = e*x + b
e^1 ln(1) = e*1 + b
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3 years ago
3926%13. I got 309 r9. What is it and what did I do wrong.
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6 0
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