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zavuch27 [327]
3 years ago
6

The area of the shaded region

Mathematics
1 answer:
antiseptic1488 [7]3 years ago
4 0

Answer:

125.66cm²

Step-by-step explanation:

so you need to find the area of the big circle and subtract it from the area of the small circle

area of a circle= π r²

small circle: substitute in what you know

a= π x 3²

a= 28.2743

big circle: substitute in what you know

a= π x 7²

a= 153.9380

now do 153.9380-28.2743=125.6637

now round this number to the nearest hundredth:

125.66cm²

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2 years ago
Tienes un triángulo equilátero con lados de 10cm, lo divides en dos partes de manera horizontal tal que el área de ambos figuras
Tanya [424]

Answer:

x = 10/√2 ≈ 7.07

Step-by-step explanation:

Comenzaremos por dividir el triángulo en dos partes y definir H, como en la figura adjunta.

Aplicando el teorema de Tales, sabemos que:

\dfrac{l/2}{H}=\dfrac{x/2}{h}\\\\\\\dfrac{l}{H}=\dfrac{x}{h}

También sabemos que, dado que el tirángulo menor es la mitad que el triángulo mayor, la relación entre áreas es:

\dfrac{A}{A_x}=\dfrac{lH/2}{xh/2}=\dfrac{lH}{xh}=2

Dado que formamos dos triángulos rectángulos, podemos despejar el valor de H como:

(l/2)^2+H^2=l^2\\\\H^2=l^2-(l/2)^2=10^2-5^2=100-25=75\\\\H^2=\sqrt{75}

Podemos entonces despejar x de la siguiente manera:

h=\dfrac{H}{l}\cdot x=\dfrac{lH}{2x}\\\\\\2x^2\dfrac{H}{l}=lH\\\\\\2x^2=l^2\\\\\\x=\dfrac{l}{\sqrt{2}}=\dfrac{10}{\sqrt{2}}\approx7.07

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