Answer:
A Pipe that is 120 cm long resonates to produce sound of wavelengths 480 cm, 160 cm and 96 cm but does not resonate at any wavelengths longer than these. This pipe is:
A. closed at both ends
B. open at one end and closed at one end
C. open at both ends.
D. we cannot tell because we do not know the frequency of the sound.
The right choice is:
B. open at one end and closed at one end
.
Step-by-step explanation:
Given:
Length of the pipe,
= 120 cm
Its wavelength
= 480 cm
= 160 cm and
= 96 cm
We have to find whether the pipe is open,closed or open-closed or none.
Note:
- The fundamental wavelength of a pipe which is open at both ends is 2L.
- The fundamental wavelength of a pipe which is closed at one end and open at another end is 4L.
So,
The fundamental wavelength:
⇒ 
It seems that the pipe is open at one end and closed at one end.
Now lets check with the subsequent wavelengths.
For one side open and one side closed pipe:
An odd-integer number of quarter wavelength have to fit into the tube of length L.
⇒
⇒ 
⇒
⇒ 
⇒
⇒ 
⇒
⇒
So the pipe is open at one end and closed at one end
.
In math, 'of' means 'multiplied by,' so 15% of 32 translates to '15% * 32.'
Now solve the equation:
x = 15% * 32
x = .15 * 32
x = 4.8
Anyway
so the recursive rule tells the relationship between the previous term and the term we want to find
given
an=2n+11
it is clear that the first term is 13
2nd term is 15
3rd term is 17
each term increases by 2
so
a term is equal to the previous term plus 2
an=a(n-1)+2
the first one is the answer
Answer:
129
Step-by-step explanation:
pls heart and give brainliest much appreciated
Answer:97 rods
Step-by-step explanation:
The number of steel rods for 95% confidence level


E=3

Substituting values


Thus 97 rods is tested