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Mumz [18]
3 years ago
6

A square field has a perimeter if 3.6km what is the length of one side in metres​

Mathematics
2 answers:
spayn [35]3 years ago
4 0

Answer:

A square field has a perimeter if 3.6km what is the length of one side in metres

Step-by-step explanation:

A square field has a perimeter if 3.6km what is the length of one side in metres

Bumek [7]3 years ago
3 0

Given,

  • Perimeter = 3.6 km = 3600m

We need to find,

  • Side of square = ?

As we know that,

  • Perimeter of square = 4 ×side

→3600=4s

→3600/4=side

→Side=900m

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Tom was selling his old games. He started out with 57 but sold 37 of them. He put the rest in boxes with 5 games in each. How ma
eduard

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Tom started out with 57 games but sold 37 of them.

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3 years ago
Kate wants to divide 20,000 peso savings between her 2 cousins. If she divides it in the ratio 2:3 between Maria and Ana, respec
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8 0
2 years ago
National data indicates that​ 35% of households own a desktop computer. In a random sample of 570​ households, 40% owned a deskt
Elan Coil [88]

Answer:

Yes, this provide enough evidence to show a difference in the proportion of households that own a​ desktop.

Step-by-step explanation:

We are given that National data indicates that​ 35% of households own a desktop computer.

In a random sample of 570​ households, 40% owned a desktop computer.

<em><u>Let p = population proportion of households who own a desktop computer</u></em>

SO, Null Hypothesis, H_0 : p = 25%   {means that 35% of households own a desktop computer}

Alternate Hypothesis, H_A : p \neq 25%   {means that % of households who own a desktop computer is different from 35%}

The test statistics that will be used here is <u>One-sample z proportion</u> <u>statistics</u>;

                                  T.S.  = \frac{\hat p-p}{{\sqrt{\frac{\hat p(1-\hat p)}{n} } } } }  ~ N(0,1)

where, \hat p = sample proportion of 570​ households who owned a desktop computer = 40%

            n = sample of households = 570

So, <u><em>test statistics</em></u>  =  \frac{0.40-0.35}{{\sqrt{\frac{0.40(1-0.40)}{570} } } } }

                               =  2.437

<em>Since, in the question we are not given with the level of significance at which to test out hypothesis so we assume it to be 5%. Now at 5% significance level, the z table gives critical values of -1.96 and 1.96 for two-tailed test. Since our test statistics doesn't lies within the range of critical values of z so we have sufficient evidence to reject our null hypothesis as it will fall in the rejection region due to which we reject our null hypothesis.</em>

Therefore, we conclude that % of households who own a desktop computer is different from 35%.

3 0
3 years ago
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