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yaroslaw [1]
3 years ago
9

What is an equation of the line that passes through the points -8,4 and -8,8

Mathematics
1 answer:
Vitek1552 [10]3 years ago
4 0

Answer:

8+8/-8-4

16/-12

4/-3

8=4/-3(-8)+b

8*3=12+b

24=12+b

12=b

y=-4/3+12

Step-by-step explanation:

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A car is traveling at a steady speed. It travels 2 1/3 miles in 3 1/2 minutes, how far will it travel in 32 minutes?
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21 1/3 miles
Divide 32 by 3 1/2, and then multiply it by 2 1/3 to get this answer
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3 years ago
A scientist inoculates​ mice, one at a​ time, with a disease germ until he finds 3 that have contracted the disease. If the prob
UkoKoshka [18]

Answer:

The probability that 8 mice are​ required is 0.2428.

Step-by-step explanation:

Given : A scientist inoculates​ mice, one at a​ time, with a disease germ until he finds 3 that have contracted the disease. If the probability of contracting the disease is two sevenths.

To find : What is the probability that 8 mice are​ required? The probability that that 8 mice are required is nothing ?

Solution :

Applying binomial distribution,

P(X=r)=^nC_r p^rq^{n-r}

Where, p is the probability of success p=\frac{2}{7}

q is the probability of failure q=1-p, q=1-\frac{2}{7}=\frac{5}{7}

n is total number of trials n=8

r=3

Substitute the values,

P(X=3)=^8C_3 (\frac{2}{7})^3 (\frac{5}{7})^{8-3}

P(X=3)=\frac{8!}{3!5!}\times \frac{8}{343}\times (\frac{5}{7})^{5}

P(X=3)=\frac{8\times 7\times 6}{3\times 2\times 1}\times \frac{8}{343}\times \frac{3125}{16807}

P(X=3)=0.2428

Therefore, the probability that 8 mice are​ required is 0.2428.

5 0
4 years ago
Enter the value of 3^3+4⋅(5^2−4^2).
Oduvanchick [21]
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3 0
3 years ago
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Answer:

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Step-by-step explanation:

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3 years ago
Answer this algebraic expression. 58 less than j
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Answer:

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