Please help me solve 3x + 4y =15 and 3x - y = 30 it is for Algebra I
2 answers:
Answer:
Step-by-step explanation:
Given the simultaneous equation
3x+4y=15. Equation 1
3x-y=30. Equation 2
Using elimination method
Sutract equation 2 from 1
Then, will have
3x-3x+4y--y=15-50. -×-=+
4y+y=-15
5y=-15
Divide Both sides by 5
y=-15/5
y=-3
From equation 2
3x-y=30
3x--3=30
3x+3=30
3x=30-3
3x=27
Divide both side by 3
x=27/3
x=9
Then, x=9 and y=-3
Answer:
x=7 y=-9
Step-by-step explanation:
Use a system of equations to solve.
3x-y=30 changes to y=-30+3x
This can then be substituted into the other equation.
3x+4(-30+3x)=15
solve for x
X=7
Now use 7 in the other equation.
y=-30+x(7)
y=-9
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