It is c 12/5
hope it helps
Y = log3 27
27 = 3^x
3^3 = 27
so x = 3
Answer:
These triangles cannot be proven congruent.
They are similar but NOT congruent.
Step-by-step explanation:
If you have at least as many equations as your have unknown variables, the 'system' is solvable (unless the equations are copies of eachother).
In this case, isolate one letter and plug it in the other. I'm going for the 2a in the bottom one (it doesn't matter)
2a - 4b = 12 => (divide by two and move the b's to the other side)
a = 6 + 2b. (plug this one into the top equation)
4(6+2b) + 6b = 10 => 24+8b+6b = 10 => 24 + 14b = 10 => 14b = -14 => b=-1
a = 6 + -2 = 4.
So a=4 and b=-1.
Assume each square is 1 unit.
The base of the large triangle is 6 units and the base of the smaller triangle is 3 units.
The scale factor is 1/2
