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4 years ago

Simplify completely quantity 6 x minus 12 over 10.

1 answer:

7 0

(6x-12)/10 factor out 2

2(3x-6)/(2(5))

(3x-6)/5 and you can factor out 3 from the numerator too

3(x-2)/5 which can be expressed as:

0.6(x-2)

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A sample of 36 observations is selected from a normal population. The sample mean is 12, and the population standard deviation i

velikii [3]

Answer: One tail test.

Step-by-step explanation:

Given : A sample of 36 observations is selected from a normal population. The sample mean is 12, and the population standard deviation is 3.

Also, The set of hypothesis to conduct a test :-

$H_0:\mu\leq10\\\\H_1:\mu>10$

The kind of test need to perform is dependent upon the alternative hypothesis.

Since, the alternative hypothesis is one tailed (right-tailed), so the test is one tail test.

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4 years ago

For the function f(x)= 1/x+1. which of these could be a value f(x) when x is close to -1

WITCHER [35]

Given the following question:

$f(x)=\frac{1}{x+1}$

Graph the function:

The value of the function of x is infinite as you see the line goes on forever. Which means your answer is option C or "10,000."

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1 year ago

In Exercises 5-7, find all the exact t-values for which the given statement is true,

bearhunter [10]

Answer: See Below

Step-by-step explanation:

NOTE: You need the Unit Circle to answer these (attached)

5) cos (t) = 1

Where on the Unit Circle does cos = 1?

Answer: at 0π (0°) and all rotations of 2π (360°)

In radians: t = 0π + 2πn

In degrees: t = 0° + 360n

******************************************************************************

$6)\quad sin (t) = \dfrac{1}{2}$

Where on the Unit Circle does $sin = \dfrac{1}{2}$

Hint: sin is only positive in Quadrants I and II

$\text{Answer: at}\ \dfrac{\pi}{6}\ (30^o)\ \text{and at}\ \dfrac{5\pi}{6}\ (150^o)\ \text{and all rotations of}\ 2\pi \ (360^o)$

$\text{In radians:}\ t = \dfrac{\pi}{6} + 2\pi n \quad \text{and}\quad \dfrac{5\pi}{6} + 2\pi n$

In degrees: t = 30° + 360n and 150° + 360n

******************************************************************************

$7)\quad tan (t) = -\sqrt3$

Where on the Unit Circle does $\dfrac{sin}{cos} = \dfrac{-\sqrt3}{1}\ or\ \dfrac{\sqrt3}{-1}\quad \rightarrow \quad (1,-\sqrt3)\ or\ (-1, \sqrt3)$

Hint: sin and cos are only opposite signs in Quadrants II and IV

$\text{Answer: at}\ \dfrac{2\pi}{3}\ (120^o)\ \text{and at}\ \dfrac{5\pi}{3}\ (300^o)\ \text{and all rotations of}\ 2\pi \ (360^o)$

$\text{In radians:}\ t = \dfrac{2\pi}{3} + 2\pi n \quad \text{and}\quad \dfrac{5\pi}{3} + 2\pi n$

In degrees: t = 120° + 360n and 300° + 360n

4 0

3 years ago

A baseball player hit 65 home runs in a season. Of the 65 home runs, 19 went to right field, 23 went to right-center field, 9

olchik [2.2K]

Answer:

a) 29.23% probability that a randomly selected home run was hit to right field

b) 29.23% probability that a randomly selected home run was hit to right field, which is not lower than 5% nor it is higher than 95%. So it was not unusual for this player to hit a home run to right field.

Step-by-step explanation:

A probability is the number of desired outcomes divided by the number of total outcomes. It is said to be unusual if it is lower than 5% or higher than 95%.

(a) What is the probability that a randomly selected home run was hit to right field?

Desired outcomes:

19 home runs hit to right field

Total outcomes:

65 home runs

19/65 = 0.2923

29.23% probability that a randomly selected home run was hit to right field

(b) Was it unusual for this player to hit a home run to right field?

29.23% probability that a randomly selected home run was hit to right field, which is not lower than 5% nor it is higher than 95%. So it was not unusual for this player to hit a home run to right field.

8 0

3 years ago

Which statement is the correct interpretation of the inequality ?4 > ?5? On a number line, ?4 is located to the left of 0 and

iragen [17]

Answer:

On a number line, -4 is located to the right of -5

Step-by-step explanation:

5 0

3 years ago

Read 2 more answers