1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
julia-pushkina [17]
3 years ago
14

Sam use 6

absmiddle" class="latex-formula">s pound of strawberries to make 441\frac1{3}{} cup of strawberry jam. HOW Manny pounds does he need to make 1 cup of strawberry jam.
SOLVE THEM IN STEPPS PLEASE< DO IT RIGHT ILL GIVE BRAINLIEST :D
Mathematics
2 answers:
bazaltina [42]3 years ago
7 0

Answer:

2\frac{1}{4} pounds of strawberries.

Step-by-step explanation:

We have been given that Same uses \frac{3}{4} pound of strawberries to make \frac{1}{3} cup of strawberry jam. We are asked to find the pounds that Sam need to make 1 cup of strawberry jam.

To find the pounds that Sam need to make 1 cup of strawberry jam, we will divide  \frac{3}{4} pound by \frac{1}{3}  as:

\text{Pounds needed to make 1 cup of strawberry jam}=\frac{3}{4}\div\frac{1}{3}

Now, we will convert the division problem into multiplication problem by flipping the 2nd fraction as:

\text{Pounds needed to make 1 cup of strawberry jam}=\frac{3}{4}\times \frac{3}{1}

\text{Pounds needed to make 1 cup of strawberry jam}=\frac{3\times 3}{4 \times 1}

\text{Pounds needed to make 1 cup of strawberry jam}=\frac{9}{4}

\text{Pounds needed to make 1 cup of strawberry jam}=2\frac{1}{4}

Therefore, Sam needs 2\frac{1}{4} pounds of strawberries to make 1 pound of jam.

PtichkaEL [24]3 years ago
4 0

\bf \begin{array}{ccll} \stackrel{strawberry}{lbs}&\stackrel{jam}{cups}\\ \cline{1-2} \frac{3}{4}&\frac{1}{3}\\\\ x&1 \end{array}\implies \cfrac{~~\frac{3}{4}~~}{x}=\cfrac{~~\frac{1}{3}~~}{1}\implies \cfrac{~~\frac{3}{4}~~}{\frac{x}{1}}=\cfrac{1}{3}\implies \cfrac{3}{4}\cdot \cfrac{1}{x}=\cfrac{1}{3} \\\\\\ \cfrac{3}{4x}=\cfrac{1}{3}\implies 9=4x\implies \cfrac{9}{4}=x\implies 2\frac{1}{4}=x

You might be interested in
Which of the tables represents a function? Table P Input Output 8 3 1 7 5 4 Table Q Input Output 9 3 9 5 4 2 Table R Input Outpu
Colt1911 [192]

Answer:

Table P represents a function

Step-by-step explanation:

* Lets explain the meaning of the function

- A function is a relation between a set of inputs and a set of outputs

 in condition of each input has exactly one output

- Ex:

# The relation {(1 , 2) , (-4 , 5) , (-1 , 5)} is a function because each x in the

   order pair has only one value of y

# The relation {(1 , 2) , (1 , 5) , (3 , 7)} is not a function because there is x

   in the order pairs has two values of y (x = 1 has y = 2 and y = 5)

* Lets solve the problem

# Table P :

- In put    : 8  ,  1  ,  5

- Out put : 3  ,  7  , 4

∵ Each input has only one output

∴ Table P represents a function

# Table Q :

- Input     : 9  ,  9  ,  4

- Out put : 3  ,  5  ,  2

∵ The input 9 has two outputs 5 and 2

∴ Table Q doesn't represent a function

# Table R :

- In put    : 7  ,  8  ,  7

- Out put : 2  ,  6  ,  3

∵ The input 7 has two outputs 2 and 3

∴ Table R doesn't represent a function

# Table S :

- In put    :  1  ,  1  ,  9

- Out put :  7 ,  5  ,  2

∵ The input 1 has two outputs 7 and 5

∴ Table S doesn't represent a function

* Table P represents a function

4 0
4 years ago
CAN SOMEONE HELP ME WITH THIS PLEASE AND THANK YOU
zhenek [66]
Of course! its 18/5!!
6 0
3 years ago
Read 2 more answers
Use the graph to evaluate the function for the given input<br> value.<br> fl-1) =<br> f(1) =
stira [4]

Answer:

f(-1) = -8

f(1) = -12

Step-by-step explanation:

-1 and 1 are inputs to the function f which is shown on the graph.

The inputs are on the x-axis so when x = -1, the graph shows that the function f at -1 is approximately -8.

When x = 1, the function f is approximately -12.

3 0
3 years ago
Read 2 more answers
Write the symbols for the probability that of all the outfielders, a player is not a great hitter.
Mumz [18]

The symbolic representation of the conditional probability

P(G'|O)  =  \frac{P(G'nO)}{P(O)}

This is a conditional probability problem ; which can be expressed explicitly as ;

  • The probability of not being a great hitter Given that the player is an outfielder
  • Recall :

Probability of A given B is defined as ;

P(A|B)  =  \frac{P(AnB)}{P(B)}

Let :

Probability that a player is an outfielders = P(O)

Probability that a player is a Great hitter = P(G)

  • Probability that a player is not a great hitter = P(G')

  • Probability that a player is not a great hitter given that he is an outfielder = P(OnG')

Therefore, we have :

P(G'|O)  =  \frac{P(G'nO)}{P(O)}

Learn more : brainly.com/question/18153040

7 0
3 years ago
Which account is an example of a contra-revenue account?
sleet_krkn [62]
A contra revenue account might be described as a revenue account that is expected to have a debit balance instead of the usual credit balance

So the answer is sales discount
3 0
3 years ago
Other questions:
  • Mr. Ann needs to assign 32 students into 8 equal groups.He says ,” i can use repeated subtraction.since i subtract 3 times, each
    15·1 answer
  • Give an example of a compound event. :) <br> - <br> (20 pts)
    8·1 answer
  • Carl and Stephen and Brittney completed in a shot put competition .Stephen's toss was 4.08 feet farther than Brittney's. Carl's
    13·2 answers
  • Help me on 56 57 59 and 60 plz ASAP
    9·1 answer
  • Solve for x using the Master Product.<br> 6x2 – 13x – 5 = 0
    14·1 answer
  • If f(x) is a third degree polynomial function, how many distinct complex roots are possible?
    11·2 answers
  • Point M lies between points L and N on LN.
    10·2 answers
  • Can I plz get help??? And a I need like a step to step solving it plzz
    10·1 answer
  • What are the solutions of the equation (2x + 3)+ 8(2x + 3) + 11 = 0? Use u substitution and the quadratic formula to
    11·1 answer
  • Can some help me calculate the value of x?
    8·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!