Question

In this diagram, bac~edf. if the area of bac= 6 in.², what is the area of edf? PLZ HELP PLZ PLZ PLZ

Answer 1

Answer:

2.7 in²

Step-by-step explanation:

Since ∆BAC and ∆EDF are similar, therefore, the ratio of their area = square of the ratio of their corresponding side lengths.

Thus, if area of ∆EDF = x, area of ∆BAC = 6 in², EF = 2 in, BC = 3 in, therefore:

$\frac{6}{x} = (\frac{3}{2})^2$

$\frac{6}{x} = (1.5)^2$

$\frac{6}{x} = 2.25$

$\frac{6}{x}*x = 2.25*x$

$6 = 2.25x$

$\frac{6}{2.25} = \frac{2.25x}{2.25}$

$2.67 = x$

$x = 2.7 in^2$ (nearest tenth)