A regular polygon<span> is equilateral (it has equal sides) and equiangular (it has equal angles). To find the </span>area<span> of a regular </span>polygon<span>, you use an apothem — a segment that joins the </span>polygon's<span> center to the midpoint of any side and that is perpendicular to that side (segment HM in the following figure is an apothem).</span>
As we know :
Dividend = Divisor × Quotient ( taking remainder as 0 )
So, Quotient = Dividend ÷ Divisor
by using the above relation we can say :
therefore, correct option is C. t ÷ 23
Answer:
D. 6x^3 + 8x
Step-by-step explanation:
2x(3x^2 + 4)
Distribute the 2x
2x(3x^2) +2x( 4)
6x^3 +8x
Answer:
z = x^3 +1
Step-by-step explanation:
Noting the squared term, it makes sense to substitute for that term:
z = x^3 +1
gives ...
16z^2 -22z -3 = 0 . . . . the quadratic you want
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<em>Solutions derived from that substitution</em>
Factoring gives ...
16z^2 -24z +2z -3 = 0
8z(2z -3) +1(2z -3) = 0
(8z +1)(2z -3) = 0
z = -1/8 or 3/2
Then we can find x:
x^3 +1 = -1/8
x^3 = -9/8 . . . . . subtract 1
x = (-1/2)∛9 . . . . . one of the real solutions
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x^3 +1 = 3/2
x^3 = 1/2 = 4/8 . . . . . . subtract 1
x = (1/2)∛4 . . . . . . the other real solution
The complex solutions will be the two complex cube roots of -9/8 and the two complex cube roots of 1/2.
