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kap26 [50]
3 years ago
7

I really need helppppp

Mathematics
1 answer:
Dmitry [639]3 years ago
6 0

Answer: the distance of the boat from the foot of the lighthouse is 290.5 feet.

Step-by-step explanation:

The right angle triangle ABC representing the scenario is shown in the attached photo.

Angle A is alternate to the angle of depression, hence, they are the same.

The height of the lighthouse represents the opposite side of the right angle triangle. The distance, x of the boat from the foot of the lighthouse represents the adjacent side of the right angle triangle.

To determine x, we would apply

the tangent trigonometric ratio.

Tan θ, = opposite side/adjacent side. Therefore,

Tan 11.1 = 57/x

x = 57/Tan 11.1 = 57/0.1962

x = 290.5 feet to the nearest tenth.

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Find the sin in the triangle
Ierofanga [76]

Answer:

.324 or 18.9 degrees

Step-by-step explanation:

rule is

sine equals opposite over hypotenuse,

cosine equals adjacent over hypotenuse, and

tangent equals opposite over adjacent

OR

soh cah toa

sine = soh = 12/37 = .324

arcsin(.324) or sin^-1(.324) in DEGREES not radians =

18.9 degrees

6 0
3 years ago
NEED ASAP!!!! A linear equation is represented by y = x + 3. The graph of which equation would be parallel to that of the equati
Gemiola [76]

Answer:

D. y = x - 3

Step-by-step explanation:

Parallel lines are when 2 lines have the same slope but different y-intercepts.

3 0
3 years ago
ABC and EDC are straight lines. EA is parallel to DB. EC = 8.1 cm. DC = 5.4 cm. DB = 2.6 cm. (a) Work out the length of AE. cm (
harkovskaia [24]

By applying the knowledge of similar triangles, the lengths of AE and AB are:

a. \mathbf{AE = 3.9 $ cm}\\\\

b. \mathbf{AB = 2.05 $ cm} \\\\

<em>See the image in the attachment for the referred diagram.</em>

<em />

  • The two triangles, triangle AEC and triangle BDC are similar triangles.
  • Therefore, the ratio of the corresponding sides of triangles AEC and BDC will be the same.

<em>This implies that</em>:

  • AC/BC = EC/DC = AE/DB

<em><u>Given:</u></em>

EC = 8.1 $ cm\\\\DC = 5.4 $ cm\\\\DB = 2.6 cm\\\\AC = 6.15 $ cm

<u>a. </u><u>Find the length of </u><u>AE</u><u>:</u>

EC/DC = AE/DB

  • Plug in the values

\frac{8.1}{5.4} = \frac{AE}{2.6}

  • Cross multiply

5.4 \times AE = 8.1 \times 2.6\\\\5.4 \times AE = 21.06

  • Divide both sides by 5.4

AE = \frac{21.06}{5.4} = 3.9 $ cm

<u>b. </u><u>Find the length of </u><u>AB:</u>

AB = AC - BC

AC = 6.15 cm

To find BC, use AC/BC = EC/DC.

  • Plug in the values

\frac{6.15}{BC} = \frac{8.1}{5.4}

  • Cross multiply

BC \times 8.1 = 6.15 \times 5.4\\\\BC = \frac{6.15 \times 5.4}{8.1} \\\\BC = 4.1

  • Thus:

AB = AC - BC

  • Substitute

AB = 6.15 - 4.1\\\\AB = 2.05 $ cm

Therefore, by applying the knowledge of similar triangles, the lengths of AE and AB are:

a. \mathbf{AE = 3.9 $ cm}\\\\

b. \mathbf{AB = 2.05 $ cm} \\\\

Learn more here:

brainly.com/question/14327552

3 0
2 years ago
3x+y=4<br> 2x+y=5<br> solve using linear combination
Advocard [28]
Idk what linear combination is but you can solve this way:
3x+y=4
-2x-y=-5
x=-1
3(-1)+y=4
-3+y=4
y=7
So x=-1 and y=7
3 0
2 years ago
Read 2 more answers
A square rests inside a regular octagon. Each shape has a side length measuring 9 inches.
Phantasy [73]

Wait so are the sides of the octagon 9 inches each or do we have to find that?

6 0
2 years ago
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