2 answers:
The probability of getting a sum of four is one out of twelve.
Answer:
There are six faces for each of two dice, giving 36 possible outcomes. If the two dice are fair, each of 36 outcomes is equally likely.
So far only 3 outcomes sum to 4 which are (1+3), (2+2) and (3+1).
Probability of getting a sum of 4 on one toss of two dice is 3/36, or 1/12.
(note since there isn't a specific # of sides I'm using 6.)
1/12
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Answer:
<5=39
Step-by-step explanation:
<2=48
<3=93
<2 and <4 are equal to each other because they are alternate interior angles
93+48=141
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Answer:
Step-by-step explanation:
-3.7+12.5=8.8
Answer:
4
Step-by-step explanation:
P={1,2,3,4,5,6}
Q={3,4,5,6,7,8,9}
PnQ={3,4,5,6}
Therefore, n(PnQ) =4
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