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Y_Kistochka [10]
3 years ago
8

WILL MARK BRAINLIEST!

Mathematics
1 answer:
ddd [48]3 years ago
4 0

<u><em>Sheridan is correct!</em></u>

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I will give brainliest<br> 7k+8=2k-37<br> Show work pleaseeeee
Artyom0805 [142]

Answer:

k = -9

Step-by-step explanation:

subtract 2k from both sides

_5k+8= -37

subtract 8

_5k = -45

divide by 5

_k = -9

6 0
3 years ago
Read 2 more answers
Please help me, I’m struggling!
Leno4ka [110]

Answer:

Multiply the numbers until you get the same denominator (Bottom number) for both fractions. I will do #1 to show you.

1/3    1/2

Both 3 and 2 go into 6, so I will use that.

When multiplying the bottom , you have to do the same to the top, so...

2/6  OR  3/6

3/6 is greater, so that is the answer.

Therefore, 1/2 is more

Another way you can do this is to draw a pizza, a section off parts of it according to the fractions.

Hope this helped.

3 0
3 years ago
Read 2 more answers
Write the slope intercept form of the equation of each line
Advocard [28]

Answer:

y = -1/3

Step-by-step explanation:

4 0
2 years ago
Radioactive Decay:
Vadim26 [7]

The question is incomplete, here is the complete question:

The half-life of a certain radioactive substance is 46 days. There are 12.6 g present initially.

When will there be less than 1 g remaining?

<u>Answer:</u> The time required for a radioactive substance to remain less than 1 gram is 168.27 days.

<u>Step-by-step explanation:</u>

All radioactive decay processes follow first order reaction.

To calculate the rate constant by given half life of the reaction, we use the equation:

k=\frac{0.693}{t_{1/2}}

where,

t_{1/2} = half life period of the reaction = 46 days

k = rate constant = ?

Putting values in above equation, we get:

k=\frac{0.693}{46days}\\\\k=0.01506days^{-1}

The formula used to calculate the time period for a first order reaction follows:

t=\frac{2.303}{k}\log \frac{a}{(a-x)}

where,

k = rate constant = 0.01506days^{-1}

t = time period = ? days

a = initial concentration of the reactant = 12.6 g

a - x = concentration of reactant left after time 't' = 1 g

Putting values in above equation, we get:

t=\frac{2.303}{0.01506days^{-1}}\log \frac{12.6g}{1g}\\\\t=168.27days

Hence, the time required for a radioactive substance to remain less than 1 gram is 168.27 days.

7 0
3 years ago
Four years from now, hozumi will be 2 years younger than 4 times her present age. which equation could be used to determine hozu
Dmitriy789 [7]

Answer:

2

Step-by-step explanation:

Four years from now: h+4

Hozumi will be 2 years younger than 4 times her present age: 4h-2

h+4=4h-2

6=3h

h=2

4 0
2 years ago
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