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KatRina [158]
3 years ago
8

Tom and Jerry's Pizza Parlor changes $8.00 for large cheese pizza. Each additional topping is $1.

Mathematics
1 answer:
Scorpion4ik [409]3 years ago
4 0

Answer:

Step-by-step explanation:

The price per pizza is $8.00 with additional toppings priced at $1.00 each.

If x represents the number of additional toppings, then the prizza price is

p(x) = $8.00 = ($1.00/topping)x, where 0 ≤ x < ∞

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the difference between seven times one number and three times a second number is 25. The sum of twice the first and five times t
inysia [295]
\left \{ {{7*x - 3*y=25} \atop {2*x + 5*y=95}} \right.

\left \{ {{7x - 3y=25}(I) \atop {2x + 5y=95}(II)} \right.

\left \{ {{7x - 3y=25}simplify*(5) \atop {2x + 5y=95}simplify*(3)} \right.

\left \{ {{35x - \diagup\!\!\!\! 15 y=125} \atop {6x + \diagup\!\!\!\! 15y=285}} \right.

\left \{ {{35x =125} \atop {6x =285}} \right.

41x = 410

\boxed{x=10}

<span>Replace the value of "x" in the second equation (II) to find the value of "y", thus:
</span>2x + 5y=95
2*(10)+5y = 95
20+5y=95
5y=95-20
5y=75
y =  \frac{75}{5}
\boxed{y=15}


The numbers (10,15)

5 0
3 years ago
Armando has collection of 25 coins . Of the 25 coins , 11 are nickles. What percent of the coins are nickles ?
Marysya12 [62]

Answer:

10%

Step-by-step explanation:

3 0
3 years ago
Answer this math quedtion <br> 40s+(2b)s+200
Elina [12.6K]
Is it supposed to be equal to something, maybe "0"? You wouldn't be able to solve this without that.
5 0
3 years ago
Two children own two-way radios that have a maximum range of 3 miles. One leaves a certain point at 1:00 P.M., walking due north
Grace [21]

Answer:

The answer is 21 minutes

Step-by-step explanation:

We use the equation Xf = Xo + vt

1) At 1:00 PM, child one leaves the starting point heading north at a constant velocity of 6 mi/hr or .1 [mi/min] (divide by 60 to convert from [mi/hr] to [mi/min])

2) He walks for 15 minutes before kid 2 starts walking. In 15 minutes he is able to cover 1.5 [mi]

  • x_{1f1} =x_{o} +v_{1} t_{1} \\x_{1f1} =0+.1(15)\\x_{1f1} =1.5 [mi]

3) Now, child 2 starts walking and we know that when the range reaches 3 miles, they won´t be able to communicate. So the sum of the final position of child 1 and child 2 must be 3[mi]

  • Child 1 final position => x_{1f} = x_{1f1} +v_{1} t\\x_{1f} =1.5+v_{1} t
  • Child 2 final position => x_{2f} =0+v_{2} t

4) Sum the equations and equate to 3

  • x_{1f} +x_{2f} =3

5) Substitute the values we already know

  • 1.5+v_{1} t+v_{2}t=3\\ 1.5+.1t+.15t=3\\1.5+.25t=3\\t=\frac{3-1.5}{.25} \\t=6 [min]

6) in 15 + 6 minutes they will be 3miles apart

7) In 21 minutes they will still be able to communicate with one another.

7 0
3 years ago
F(x)=3/2(x-2)^2-24 <br>put this in standard form​
gregori [183]

Answer:

f(x) = 3x^2 - 12x -  36.

Step-by-step explanation:

f(x) =3 /2(x - 2)^2 - 24

f(x) = 3/2 (x^2 - 4x + 4) - 24

f(x) = 3/2 x^2 - 6x + 6 - 24

f(x) = 3/2 x^2 - 6x - 18

Multiply through by 2:

f(x) = 3x^2 - 12x -  36.

6 0
3 years ago
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