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mars1129 [50]
3 years ago
13

On a number line, the distance from zero to -8 to 8? 8^2=64 |-8|=8 |-8|=-8 0+8=8

Mathematics
1 answer:
solmaris [256]3 years ago
6 0
The answer should be B.
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(5.2x + 36.4x + 52)/ (2.6x +13)
g100num [7]
Combine like terms in the first set and get
41.6x +52/2.6x + 13

I got 16x + 4
4 0
3 years ago
Please help me answer this question
SOVA2 [1]
Well knowing that it’s 5 1/4 and the cost of paint is 13.99, I’m going to assume to multiply by the given product which is 13.99 by one quarter (which is 25)
8 0
3 years ago
A rectangular prism has a length of 3/4 cubic inch and a width of 1/2 inch. The volume is 21/32 cubic inch. Find the height of t
Oliga [24]
21 / 32 = (3/4) * (1/2) * height

21 / 32 = (3 / 8) * height

21 / 32 * (3 / 8) = height =

63 / 256 inches



7 0
3 years ago
Read 2 more answers
When running a 100 meter race Bill reaches his maximum speed when he is 45 meters from the starting line and 5 seconds have elap
Mkey [24]

Bill's speed is constant after 5 seconds and 45 meters into the race.

Correct responses:

a. Bill's maximum speed is 8 m/s

b. 24 meters

c. 57 meters

<h3>Methods used to calculate speed and distance traveled</h3>

Given parameters are;

The distance of the race = 100 meter

Distance at which Bill reaches maximum speed = 45 meters

Speed Bill maintains after 5 seconds = The maximum speed

Time at which Bill is 85 meters from the starting line = 10 seconds after start

a. Required;

Bill's maximum speed in meters.

Solution:

Distance Bill runs at maximum speed, d = 85 m - 45 m = 40 m

Time at which Bill runs the 40 m at maximum speed, <em>t</em> = 10 s - 5 s = 5 s

Speed = \mathbf{\dfrac{Distance}{Time}}

Therefore;

  • Bill's \  maximum \ speed = \dfrac{40 \ m}{5 \ s} = \underline{8 \ m/s}

b. i. Required:

The distance Bill will run for 3 seconds at the maximum speed;

Solution:

Distance,<em> s</em> = Speed, <em>v</em> × Time, <em>t</em>

<em />

The distance traveled at maximum speed in 3 seconds is therefore;

Distance = 8 m/s × 3 s = 24 m

The distance Bill travels in 3 seconds at the maximum speed is 24 meters.

ii) The distance Bill travels at 8 seconds after start, is given as follows;

Distance traveled in the first 5 seconds = 45 meters

Distance traveled in the next 3 seconds = 24 meters

Therefore;

  • Bill's distance from the starting line 8 seconds after start is 45 meters + 25 meters = <u>69 meters</u>

c. Bill's distance 6.5 seconds after the start of the race is given as follows;

Distance traveled in the first 5 seconds = 45 meters

Distance traveled in the next 1.5 seconds = 1.5 s × 8 m/s = 12 meters

  • Bill's distance from the starting line 6.5 seconds after start of the race = 45 meters + 12 meters = <u>57 meters</u>

Learn more about distance, speed, time, relationship here:

https://brainly.in/question/49075584

6 0
2 years ago
Food inspectors inspect samples of food products to see if they are safe. This can be thought of as a hypothesis test with the f
Molodets [167]

Answer:

b. type II

Step-by-step explanation:

given that food inspectors  inspect samples of food products to see if they are safe. This can be thought of as a hypothesis test with the following hypotheses.

H0: the food is safe

Ha: the food is not safe

It was concluded from the hypothesis test that the food is safe while it was not actually safe.

This is a case of false acceptance of null hypothesis when it is false.

In hypothesis test, there are two errors. a type I error is the rejection of a true null hypothesis  while a type II error is the non-rejection of a false null hypothesis

So this is type II error because we did not reject a false null hypothesis.

8 0
3 years ago
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