Hello,
Part A:
f(2)=4*2²=16
f(1)=4*2^1=8
2-1=1
(f(2)-f(1))/(2-1)=(16-8)/1=8 ; r_1=8
f(3)=4*2^3=32
f(4)=4*2^4=64
(f(4)-f(3))/(4-3)=(64-32)/1=32 ; r_2=32
Part B:
r_2=32=4*8=4*r_1
Explainations:
(4*2^2-4*2^1)/(2-1)=4*2^1(2-1)=4*2
(4*2^4-4*2^3)/(4-3)=4*2^3*(2-1)=4*8=(4*2)*4
I am not sure if you gave all of the information but if you did A because A > B. Did I miss something?
Answer:
C it was the fastest way to do it when I was in class
-2/3x+9=4/3x-3
+3 +3
-2/3x+12=4/3x
+2/3x +2/3x
12=6/3x
12=2x
x=6
x=6
