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3 years ago

Can anybody help me that knows this stuff?

Mathematics

1 answer:

Marysya12 [62]3 years ago

8 0

You have you break it downn like you would order of operations and u should get your answer

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What the answer is and how?

sladkih [1.3K]

Answer:

PerimeterFigure= pi*DIameter/2= 1.5*pi ft.

Step-by-step explanation:

The perimeter is the length of the figure, since we are dealing with an semi-circle, we can use the perimeter equation for a full circle and divide it by half.

Perimeter= 2pi*R= pi*Diameter.

Since Our figure is a semi circle, as we say earlier, we now will divide the above result by half.

PerimeterFigure= pi*DIameter/2= 1.5*pi ft.

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2 years ago

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vladimir2022 [97]

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3 years ago

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2 years ago

Solve x^2+3x+2=0 using the quadratic formula

zzz [600]

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Step-by-step explanation:

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3 years ago

I really need help with this. Can anyone help me please?

I am Lyosha [343]

Answer:

$f(x)=(x-3)(x^2+4x+8)$

Step-by-step explanation:

A polynomial function is given by the form:

$f(x)=a(x-p)(x-q)...$

Where a is the leading coefficient, and p and q are the roots (more can be added if necessary).

Our zeros are 3 and (-2 + 2i).

And our leading coefficient a = 1.

Furthermore, by the Complex Root Theorem, if (-2 + 2i) is a zero, then (-2 - 2i) must also be a zero.

So, by substitution, we acquire:

$f(x)=1(x-(3))(x-(-2+2i))(x-(-2-2i))$

Simplify:

$f(x)=(x-3)(x+2-2i)(x+2+2i)$

Expand the second and third factors:

$\begin{aligned} &=(x+2-2i)x+(x+2-2i)(2)+(x+2-2i)(2i)\\&= (x^2+2x-2ix)+(2x+4-4i)+(2ix+4i-4i^2)\\&=(x^2)+(2x+2x)+(-2ix+2ix)+(-4i+4i)+(4-4i^2)\\&=x^2+4x+(4+4)\\&=x^2+4x+8 \end{aligned}$

Therefore, our polynomial function of least degree and the given zeros will be:

$f(x)=(x-3)(x^2+4x+8)$

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2 years ago