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klasskru [66]
3 years ago
5

On a trolley ride around an amusement park, a child traveled from one signpost to a second signpost at a constant speed of 125 m

eters per minute. Was the distance that the child traveled from the first signpost to the second signpost greater than 0.8 kilometer? (1 kilometer = 1,000 meters)
Physics
1 answer:
7nadin3 [17]3 years ago
6 0

Question

It took less than 450 seconds for the child to travel from the first signpost to the second signpost.

Answer:

Yes, the child took less than 450 seconds for the child to travel from the first signpost to the second signpost

Explanation:

Speed=\frac {125}{60}=2.083333333 m/s\approx 2.083 m/s

Distance=speed* time

Distance=2.083*450=937.5 m=0.9375 Km

For the child to travel 800 m, it required only \frac {800}{2.083}=384 seconds

Therefore, it's proper to conclude that it took less than 450 seconds for the child to travel from the first signpost to the second signpost.

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The sound from a loud speaker has an intensity level of 80 db at a distance of 2.0m. Consider the speaker to be a point source,
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Answer:

2.83m

Explanation:

The information that we have is

Intensity at 2.0 m: I=80dB and r_{1}=2m

we need an intensity level of: I_{2}=40dB

thus, we are looking for the distance r_{2}.

which we can find with the law for intensity and distance:

(\frac{r_{2}}{r_{1}} )^2=\frac{I_{1}}{I_{2}}

we solve for r_{2}:

\frac{r_{2}}{r_{1}}=\sqrt{\frac{I_{1}}{I_{2}} }\\\\r_{2}=r_{1}\sqrt{\frac{I_{1}}{I_{2}} }

and we substitute the known values:

r_{2}=(2m)\sqrt{\frac{80dB}{40dB} }\\\\r_{2}=(2m)\sqrt{2}\\ r_{2}=2.83m

at a distance of 2.83m the intensity level is 40dB

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3 years ago
A heated piece of metal cools according to the function c(x) = (.5)^(x _ 11), where x is measured in hours. A device is added th
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Explanation:

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Answer:

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Interpolation can be a little easier than extrapolation.

Interpolation does not require one to extend the already existing data points, where extrapolation requires elaboration of the pattern, curve, or line.

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This is a statistical method used to predict unknown values for points outside the range of the recorded data. It is used to extend a known sequence of values beyond the sampled area

Extrapolation: with Extrapolation, we can be less confident with the unknown values derived using this method. The method includes values from outside the sampled area, which makes the predictions diverge away from the true values. In curve fitting, this method is not preferred.

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