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White raven [17]
3 years ago
10

More or less friction glass

Physics
1 answer:
pantera1 [17]3 years ago
7 0
More friction because it's smooth
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The acceleration vector of a particle in uniform circular motion:___________
pashok25 [27]

(B)

Explanation:

Centripetal means "towards the center" so the acceleration vector of an object undergoing UCM is always pointed towards the center.

4 0
3 years ago
HELP ASAP PLZZZZZZ
malfutka [58]
B because the electrons are moving to create a new form. Chemical energy is changing the form.


Hope this helps.
5 0
4 years ago
Question 20
fenix001 [56]

Answer:

  (b)  Water

Explanation:

The density of the liquid is found by dividing its mass by its volume.

__

<h3>mass</h3>

The mass of the liquid is the difference in mass between the full and empty graduated cylinder:

  liquid mass = (145 g) -(45 g) = 100 g

<h3>volume</h3>

The cylinder is said to contain 100 mL of the liquid, so that is the volume of interest.

<h3>density</h3>

The ratio of mass to volume is the liquid's density:

  ρ = (100 g)/(100 mL) = 1 g/mL

This density identifies the most likely liquid as water.

8 0
2 years ago
When a car climbs a hill, it has only potential energy<br> True or false ​
Dmitriy789 [7]

Answer:

On the way back up the hill, the car converts kinetic energy to potential energy. In the absence of friction, the car should end up at the same height as it started. ... The total energy of the ball stays the same but is continuously exchanged between kinetic and potential forms.

Explanation:

hope it helps :D

7 0
3 years ago
Read 2 more answers
Red light of wavelength 633 nm from a helium-neon laser passes through a slit 0.400mm wide. The diffraction pattern is observed
kogti [31]

Answer:

a)y_{first}=5.3mm

b)y_{second}=10.6-5.3 =5.3 mm  

Explanation:

a)

The width of the central bright in this diffraction pattern is given by:

y=\frac{m\lambda D}{a} when m is a natural number.

here:

  • m is 1 (to find the central bright fringe)                
  • D is the distance from the slit to the screen
  • a is the slit wide
  • λ is the wavelength

So we have:

y_{first}=\frac{633*10^{9}*3.35}{0.0004}

y_{first}=5.3mm

b)

Now, if we do m=2 we can find the distance to the second minima.

y_{2}=\frac{2*633*10^{9}*3.35}{0.0004}

y_{2}=10.6 mm

Now we need to subtract these distance, to get the width of the first bright fringe :

y_{second}=10.6-5.3 =5.3 mm    

I hope it heps you!

     

4 0
3 years ago
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