Answer:
Probability that event will have both red marbles will be 2.3% or 0.023.
Step-by-step explanation:
Given:
Total red marbles=5
Total blue marbles=25
Total number of marbles =30
To Find:
The probability that both are red without replacement of marbles.
Solution:
Now
Total sample space is 30 and total red marbles are 5
For a event that getting red marble probability is ,
=Total red marbles /total marbles.
=5/30
=1/6
So probability if getting red marble is 1/6
<em>Now for second chance there will be 4 red marbles remaining and 29 total marbles so,</em>
In second chance probability if getting red marble will be
=total red marbles present/total marbles remaining
=4/29
Now ,
The required probability will be getting both at a time
i.e probability getting red AND red marble so here AND operator which means multiple both the probability.
Probability both will have red =1/6*4/29
=4/(29*6)=2/(29*3)
=0.022988
=0.023
=2.3 %
Answer:
the answer would be D
Step-by-step explanation:
I believe it is the first one but I might be wrong.
<h3>
♫ - - - - - - - - - - - - - - - ~Hello There!~ - - - - - - - - - - - - - - - ♫</h3>
➷ Use the expression "x + 2" to work this out
1 + (1 + 2) + (3 + 2) + (5 + 2) + (7 + 2) + (9 + 2) + (11 + 2 ) + (13 + 2) = 64
He will have saved $64
<h3><u>
✽</u></h3>
➶ Hope This Helps You!
➶ Good Luck (:
➶ Have A Great Day ^-^
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