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bearhunter [10]
3 years ago
14

To earn an A in an algebra course, a student must have a test average of at least 90. Mary has grades of 95, 82, 88 on her first

three algebra tests. What minimum score does Mary need to make on her fourth test to earn an A in her algebra course?
Mathematics
1 answer:
Fofino [41]3 years ago
5 0

Answer: Mary need to make at-least 95 on her fourth test to earn an A in her algebra course.

Step-by-step explanation:

Let x be the grades scored by Mary in the fourth algebra test.

Mary has grades of 95, 82, 88 on her first three algebra tests.

Then, the combined scores in four test will become = 95+82+88+x =  265+x

Average score = (Sum of all scores) ÷ (Number of tests)

=\dfrac{265+x}{4}

As per given ,

To earn an A in an algebra course, a student must have a test average of at least 90.

i.e. Average score ≥ 90

\Rightarrow\ \dfrac{265+x}{4}\geq90\\\\\Rightarrow\ 265+x\geq 90\times4=360\\\\\Rightarrow\ x\geq360-265 =95\\\\\Rightarrow\ x\geq90

Hence, Mary need to make at-least 95 on her fourth test to earn an A in her algebra course.

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Answer:

Function.  

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Step-by-step explanation:

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5 0
3 years ago
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Answer:

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Step-by-step explanation:

We can define the following notaton for the events:

A = It rains over the Saturday

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We have the probabilities for these two events given:

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And we are interested on the probability  that it rains over the weekend (either Saturday or Sunday), so we want to find this probability:

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And since we are assuming the events independent we can find the probability of intersection like this:

P( A \cap B) = P(A) *P(B) = 0.34*0.32 = 0.1088

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And rounded we got P(A \cup B ) = 0.551

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6 0
3 years ago
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3 years ago
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Sveta_85 [38]

Answer:

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5 0
3 years ago
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