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Rufina [12.5K]
3 years ago
9

Consider the average daily winter temperature and your heating bill- is there likely to be a correlation? If so does the correla

tion reflect a causal relationship? Explain
Mathematics
2 answers:
creativ13 [48]3 years ago
7 0
The answer to this is that t<span>here is a negative correlation and a causal correlation. The higher the average daily winter temperature the lower your heating bill.</span>
pickupchik [31]3 years ago
3 0

Answer:

There is likely to be a correlation and this correlation reflect a causal relationship

Step-by-step explanation:

If you have this two variables:

T: The average daily winter temperature (°F)

H: heating bill ($)

you can notice that when the average daily winter temperature decreases you must increase the heating energy and that leads to heating bill increases to.

Therefore you can say that when the temperature decreases, the heating bill increases.

This two variables have a negative correlation (the value of one variable increases, the other decreases).

and there is a causal relationship because if the occurrence of the first causes the other. In this case The average daily winter temperature event is called the cause and the heating bill event is called the effect.

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Perimeter of a semicircle if it’s straight length is 10mm
Ksenya-84 [330]

Here's your answer, I hope you understand this. 30.9cm

6 0
3 years ago
X is a normally Distributed random variable with a standard deviation of 4.00. Find the mean of X when 64.8% of the area lies to
Cerrena [4.2K]

Answer:

7

Step-by-step explanation:

σ = 4 ; μ =?

8.52 to the left of X

.

P(X < 8.52) = 64.8%

P(X < 8.52) = 0.648

Using the Z relation :

(x - μ) / σ

P(Z < (8.52 - μ) / 4)) = 0.648

The Z value of 0.648 of the lower tail is equal to 0.38 (Z probability calculator)

Z = 8.52 - μ / 4

0.38 = 8.52 - μ / 4

0.38 * 4 = 8.52 - μ

1.52 = 8.52 - μ

μ = 8.52 - 1.52

μ = 7

5 0
3 years ago
Consider a tank used in certain hydrodynamic experiments. After one experiment the tank contains liters of a dye solution with a
Alja [10]

Answer:

t = 460.52 min

Step-by-step explanation:

Here is the complete question

Consider a tank used in certain hydrodynamic experiments. After one experiment the tank contains 200 liters of a dye solution with a concentration of 1 g/liter. To prepare for the next experiment, the tank is to be rinsed with fresh water flowing in at a rate of 2 liters/min, the well-stirred solution flowing out at the same rate.Find the time that will elapse before the concentration of dye in the tank reaches 1% of its original value.

Solution

Let Q(t) represent the amount of dye at any time t. Q' represent the net rate of change of amount of dye in the tank. Q' = inflow - outflow.

inflow = 0 (since the incoming water contains no dye)

outflow = concentration × rate of water inflow

Concentration = Quantity/volume = Q/200

outflow = concentration × rate of water inflow = Q/200 g/liter × 2 liters/min = Q/100 g/min.

So, Q' = inflow - outflow = 0 - Q/100

Q' = -Q/100 This is our differential equation. We solve it as follows

Q'/Q = -1/100

∫Q'/Q = ∫-1/100

㏑Q  = -t/100 + c

Q(t) = e^{(-t/100 + c)} = e^{(-t/100)}e^{c}  = Ae^{(-t/100)}\\Q(t) = Ae^{(-t/100)}

when t = 0, Q = 200 L × 1 g/L = 200 g

Q(0) = 200 = Ae^{(-0/100)} = Ae^{(0)} = A\\A = 200.\\So, Q(t) = 200e^{(-t/100)}

We are to find t when Q = 1% of its original value. 1% of 200 g = 0.01 × 200 = 2

2 = 200e^{(-t/100)}\\\frac{2}{200} =  e^{(-t/100)}

㏑0.01 = -t/100

t = -100㏑0.01

t = 460.52 min

6 0
3 years ago
Ms evans paycheck is $850 a week.If she works 49 hours per week, how muxh does she make an hour
Aneli [31]
She would make about 17.35 because $850 divided by 49 is 17.3469388 rounded is 17.35
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3 years ago
B. Why does using FOIL on polynomial expressions match so closely to integer
Anastasy [175]
FOIL is a mnemonic rule for multiplying binomial (that is, two-term) algebraic expressions.
FOIL abbreviates the sequence "First, Outside, Inside, Last"; it's a way of remembering that the product is the sum of the products of those four combinations of terms.

For instance, if we multiply the two expressions
(x + 1) (x + 2)
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x times x (the First terms of each expression)
x times 2 (the Outside pair of terms)
1 times x (the Inside pair of terms)
1 times 2 (the Last terms of each expression)
and so
(x + 1) (x + 2) = x^2 + 2x + 1x + 2 = x^2 + 3x + 2
[where the ^ is the usual way we indicate exponents here in Answers, because they're hard to represent in an online text environment].

Now, compare this to multiplying a pair of two-digit integers:
37 × 43
= (30 × 40) + (30 × 3) + (7 × 40) + (7 × 3)
= 1200 + 90 + 280 + 21
= 1591

The reason the two processes resemble each other is that multiplication is multiplication; the difference in the ways we represent the factors doesn't make it a fundamentally different operation.
7 0
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