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raketka [301]
3 years ago
9

A cone with a mass of 6 g has a radius measuring 5 cm and a height of 2 cm. What is its density?

Mathematics
2 answers:
White raven [17]3 years ago
8 0

Answer:

D.0.11 g/ cm3

Step-by-step explanation:

Hello

the density is a scalar magnitude referred to the amount of mass in a given volume of a substance or a solid object.it is given by:

density\ of\ an \ object =\frac{mass\ of\ the\ object}{volume of\ the\ object}

also, the volume of a cone is

Volume={\frac{\pi *r^{2} *h}{3} }

Step 1

combine the equations

density\ of\ an \ object =\frac{mass\ of\ the\ object}{volume of\ the\ object}\\\\replace\ the\ volume\\density\ of\ an \ object =\frac{mass\ of\ the\ object}{ \frac{\pi *r^{2} *h}{3} }

Step 2

put the values into the equation

d=\frac{mass\ of\ the\ object}{ \frac{\pi *r^{2} *h}{3} }\\let\\radius= 5 cm\\heigth= 2 cm\\mass = 6 g\\\\\\d=\frac{6 g}{ \frac{\pi *(5cm)^{2} *(2cm)}{3} }\\d=\frac{18 g}{50 \pi cm^{3}} \\d=0.11 \frac{g}{cm^{3}}

d=0.11g/ cm3

Have a great day

AlekseyPX3 years ago
7 0

Volume of a cone is equal to pi*r^2*(h/3)

3.14*5^2*2/3 = 52.36 cubic cm.

Density = mass/volume

 6 grams/ 52.36 cm^3= 0.1146

Round to 2 decimal places to get D.0.11 g/cm^3

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Step-by-step explanation:

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Given: k(x) = 5x - 1, h(x) = -3x - 1

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To find point of intersection(if any), we need to set the functions equal as at the point of intersection the (x, y) value will be same for both of the lines.

Therefore, k(x) = h(x)

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Know more about "point of intersection" problems here: brainly.com/question/16929168

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8 0
1 year ago
1) What radius of a circle is required to inscribe an equilateral triangle with an area of 15.588 in2 and an altitude of 5.196 i
Andrej [43]
We know that
 the distance from the centroid of the triangle to one of the vertices is the radius of the circle <span>required to inscribe an equilateral triangle.

[distance </span>centroid of the triangle to one of the vertices]=(2/3)*h
h=the <span>altitude  of the equilateral triangle-----> 5.196 in
so
</span>[distance centroid of the triangle to one of the vertices]=(2/3)*5.196
[distance centroid of the triangle to one of the vertices]=3.464 in----> 3.5 in

the radius is equal to the distance of the centroid of the triangle to one of the vertices
hence
the radius is 3.5 in

the answer is
the radius is 3.5 in

8 0
3 years ago
Read 2 more answers
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