6000=2560(1+0.052)^t
Solve for t
t=log(6,000÷2,560)÷log(1+0.052)
t=16.8 years
Answer:
B. Square
Step-by-step explanation:
When in doubt, it can help to plot the points on a graph.
__
By looking at the coordinate values, you see that the first two points have the same y-coordinate (0) and the other two points have the same y-coordinate (-4). These points are on horizontal lines that are 4 units apart.
Looking at the x-coordinates, you see that one pair of points has x-coordinates 4, and the other pair has x-coordinates 8. That is, these pairs of points are on vertical lines that are 4 units apart.
Vertical and horizontal lines are at right angles to each other. That means the figure must be a rectangle or square. The lengths of the sides are all 4 units, so the figure is a square.
Answer: Answers provided below in sequential order.
Step-by-step explanation: UV = 12(3)-1
(They said that x = 3)
UV = 35 (12*3-1)
70 = TV
TU = UV
8x + 11 = 12x - 1
-4x = 10
x = -10/4 or -5/2 (simplified)
TU = 8 (3) + 11
TU = 35 (24+11)
Part 1) we know that
m∠5=44° m∠11=86°
m∠2=m∠5------> by vertical angles
m∠2=44°
m∠13=m∠11------> by vertical angles
m∠13=86°
m∠12+m∠13=180°-----> supplementary angles
m∠12=180-86-----> m∠12=94°
m∠14=m∠12----> by vertical angles
m∠14=94°
m∠1=m∠11----> by corresponding angles
m∠1=86°
m∠4=m∠1----> by vertical angles
m∠4=86°
m∠2+m∠1+m∠6=180
m∠6=180-(86+44)----> 50°
m∠6=50°
m∠3=m∠6----> by vertical angles
m∠3=50°
m∠8=m∠3----> by corresponding angles
m∠8=50°
m∠8+m∠7=180°-----> supplementary angles
m∠7=180-50----> 130°
m∠7=130°
m∠10=m∠6----> by corresponding angles
m∠10=50°
m∠10+m∠9=180°-----> supplementary angles
m∠9=180-50-----> 130°
m∠9=130°
the answers Part 1) are
m∠1=86°
m∠2=44°
m∠3=50°
m∠4=86°
m∠5=44°
m∠6=50°
m∠7=130°
m∠8=50°
m∠9=130°
m∠10=50°
m∠11=86°
m∠12=94°
m∠13=86°
m∠14=94°
Part 2)
a) what is m∠TPR?
in the right triangle PTR
m∠PTR+m∠TPR+m∠TRP=180° ( the sum of internal angles of triangle is equal to 180 degrees)
m∠PTR=30°
m∠TRP=90°
so
m∠TPR=180-(90+30)----> 60°
the answer Part 2a) is
m∠TPR=60°
b) what is the length in inches of segment PR?
in the right triangle PTR
sin 30=PR/TP-----> PR=TP*sin 30-----> PR=14*(1/2)----> 7 in
the answer Part 2b) is
PR=7 in
c) what is the length in inches of segment TR?
in the right triangle PTR
cos 30=TR/PT-----> TR=PT*cos 30-----> TR=14*(√3/2)---> TR=7√3 in
the answer Part 2c) is
TR=7√3 in
d) what is the length in inches of segment PQ?
in the right triangle PQR
PR=7 in
RQ=PR-----> by angle 45°
so
RQ=7 in
applying the Pythagoras Theorem
PQ²=RQ²+PR²-----> 7²+7²-----> PQ²=98-----> PQ=√98 in---> PQ=7√2 in
the answer Part 2d) is
PQ=7√2 in
Part 3) Patrice buys a block of wax in the shape of a right rectangular prism. The dimensions of the block are 20 cm by 9 cm by 8 cm.
<span><span>(a) </span>What is the volume of the block?
volume of the prism=20*9*8-----> 1440 cm³
the answer Part 3 a) is
the volume of the block is 1440 cm³
<span>
Patrice melts the wax and creates a candle in the shape of a circular cylinder that has a diameter of 10 cm and a height of 15 cm.<span>(b) </span>To the nearest centimeter, what is the volume of the candle?
</span></span>volume of a cylinder=pi*r²*h
diameter=10 cm
radius r=10/2----> 5 cm
h=15 cm
volume of a cylinder=pi*5²*15----> 1177.5 cm³-----> 1178 cm³
the answer Part 3b) is
the volume of the candle is 1178 cm³
<span>Patrice decides to use the remaining wax to create a candle in the shape of a cube.<span>(c) </span>To the nearest centimeter, what is the length of the side of the cube?
</span>
the remaining wax=volume of the prism-volume of a cylinder
=1440-1178-----> 262 cm³
volume of a cube=b³
where b is the length side of the cube
262=b³-------b=∛262-----> b=6.40 cm-----> b=6 cm
the answer Part 3c) is
the length of the side of the cube is 6 cm
