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Hitman42 [59]
3 years ago
5

Clock wise angle from minutes hand to hour hand at 7 o'clock is what (a)240° (b)230° (c)220° (d)210° (e)200°

Mathematics
2 answers:
AlladinOne [14]3 years ago
7 0

Answer:

Option D) Angle at 7 o'clock = 210 degrees

Step-by-step explanation:

The whole clock = 360 degrees

Every 1 hour = 360/12

Every 1 hour = 30 degrees

Angle at 7 o'clock = 30*7

Angle at 7 o'clock = 210 degrees

lord [1]3 years ago
6 0

Answer:

d

Step-by-step explanation:

At 7 o' clock the minute hand is at 12 and the hour hand at 7

There is 360° in a complete revolution, thus between 7 and 12

angle = \frac{7}{12} × 360° = 7 × 30° = 210° → d

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Graph the inequality.<br> 2x+5y&gt; -15
Sedbober [7]

Answer: See attached

Step-by-step explanation:

   [] Since the inequality uses greater than (>) and <em>not</em> greater than or equal to (≥), the line will be dashed.

   [] The inequality is greater than (>) so we will shade above the line as values "above" are greater.

5 0
2 years ago
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A)line a and line b<br> B)line b and line c<br> C)line b and line d<br> D) line c and line d
jarptica [38.1K]

A)line a and line b is your answer.

6 0
3 years ago
What is the length of AA' , rounded to the nearest hundredth? Type a numerical answer is the space provided. Do not type spaces
inna [77]
Coordinate of A are (0,0)
Coordinates of A' are (5,2)

We can find the distance from A to A' using the distance formula:

AA'= \sqrt{(5-0)^{2}+ (2-0)^{2}  } \\  \\ &#10;AA'= \sqrt{25+4} \\  \\ &#10;AA'= \sqrt{29} \\  \\ &#10;AA'=5.39

Thus, rounded to nearest hundredth, AA' is equal to 5.39
3 0
3 years ago
The marching band organises 80 students in the six lines how many students are in each line and how many students are left over
Bogdan [553]
80 ÷6=13
13×6=78
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4 0
3 years ago
Read 2 more answers
Can someone please teach me how to do this? You can please do like 2 questions and please explain exactly how you got the answer
spayn [35]

All of these questions require one thing: trigonometric functions.

There are 3 main trigonometric functions, which can only be used on right triangles: sine, cosine, and tangent.

Sine = opposite / hypotenuse

Cosine = adjacent / hypotenuse

Tangent = opposite / adjacent

When trying to figure out what function to use, we always start by looking from the angle. Take problem a, for example. Looking from angle E, of which the value is not given, we have the side opposite and the side adjacent. Therefore, we should use the tangent function.

---The hypotenuse is always the longest side of the triangle. It is never considered the opposite or adjacent side.

Let's set up our function with the given information from problem a.

tan(x) = 9.7 / 5.2

---The tangent of an unknown angle is equal to the quotient of the opposite side and the adjacent side.

Now, solving for the value of x will require a calculator. We'll need to use what's called an inverse trigonometric function. Most calculators have these directly above the regular trigonometric functions, and the inverse functions are accessed using a "second" key.

---Ensure that your calculator is in degrees, not radians!

x = tan^-1(9.7 / 5.2)

x = 61.805 = 62 degrees

Next, let's take a look at problem b. This time, we're solving for a side length instead of an angle. But, we're still going to start by looking from our angle.


Looking from the 38 degree angle, we are given the adjacent side and an unknown hypotenuse. Therefore, we should use the cosine function.

cosine(38) = 53.1 / r

---The cosine of a 38 degree angle is equal to the quotient of 53.1 and an unknown hypotenuse, r.

Use your algebra skills to isolate the variable r.

r * cosine(38) = 53.1

r = 53.1 / cosine(38)

---From here, all you need to do is plug this into your calculator. Since we are solving for a side length (and given an angle), we are just using the regular trigonometric function buttons on the calculator.

r = 67.385 = 67.4 units

Hope this helps!

4 0
2 years ago
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