Answer:
WXR=33
Step-by-step explanation:
Answer:
The 93% confidence interval for the true proportion of masks of this type whose lenses would pop out at 325 degrees is (0.3154, 0.5574). This means that we are 93% sure that the true proportion of masks of this type whose lenses would pop out at 325 degrees is (0.3154, 0.5574).
Step-by-step explanation:
In a sample with a number n of people surveyed with a probability of a success of
, and a confidence level of
, we have the following confidence interval of proportions.

In which
z is the zscore that has a pvalue of
.
For this problem, we have that:

93% confidence level
So
, z is the value of Z that has a pvalue of
, so
.
The lower limit of this interval is:

The upper limit of this interval is:

The 93% confidence interval for the true proportion of masks of this type whose lenses would pop out at 325 degrees is (0.3154, 0.5574). This means that we are 93% sure that the true proportion of masks of this type whose lenses would pop out at 325 degrees is (0.3154, 0.5574).
It is 4pi/7, or b. Just want to help ;)
Answer:
82.5% and 17.5%
Step-by-step explanation:
The telemarketer made 200 phone calls and only 35 people signed up. Therefore, we need to find the amount of people who didnt.
200 - 35 = 165
165 people did not sign up.
This meants that the frequency of getting a customer is 35/200 and not is 165/200. In percentages,
The relative frequency of not getting a customer is 82.5%
The relative frequency of getting a customer is 17.5%