Solve for cos(t) and sin(t):
x = 2 + 3 cos(t) ⇒ cos(t) = (x - 2)/3
y = 1 - sin(t) ⇒ sin(t) = 1 - y
Recall the Pythagorean identity,
sin²(t) + cos²(t) = 1
It follows that
((x - 2)/3)² + (1 - y)² = 1
or
(x - 2)²/9 + (y - 1)² = 1
Answer:
i need a picture to answer you question the question in very confusing
Step-by-step explanation:
You need to know: how many roots there are IS THE ANSWER to your question
Answer:
27
Step-by-step explanation:
Tₙ=n-3
T₃₀=30-3=27
