Hello,
x^3+7x^2+10x-6=x^3+3x^2+4x^2+12x-2x-6
=x²(x+3)+4x(x+3)-2(x+3)
=(x+3)(x²+4x-2)
=(x+3)(x+2-√7)(x+2+√7)
zeroes={-3,-2+√7,-2-√7}
Answer:
70
Step-by-step explanation:
Opposite Angles are supplementary in cyclic quadratlerials.
Answer:
I'm sorry I didn't understand so can u plz
