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3 years ago

Select all pairs of alternate interior angles. Assume the lines are parallel.

Mathematics

2 answers:

Angelina_Jolie [31]3 years ago

4 0

The answers should be
3 and 6
4 and 5

Digiron [165]3 years ago

3 0

Answer:

6 y 3

Step-by-step explanation:

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Daredevil Danny takes a practice jump as shown on the graph below. Complete the steps to determine the equation for the paraboli

solniwko [45]

Answer:

Step 4

part a: no answer yet still having trouble showing my work

part b:

-0.125(x-24)^2+50

-0.125(x-24)(x-24)+50

-0.125(x^2-24x-24x+576)+50

-0.125(x^2-48x+576)+50

-0.125x^2+6x-75+50

-0.125x^2+6x-22

a=-0.125

b=6

c=-22

part c: yes he went through

part d:

plug in roots (4,0) and (44,0)

if x is 4 and y is 0

0=-0.125(4)^2+6(4)-22

0=-2+24-22

0=-2+2

0=0

if x=44 and y=0

0=-0.125(44)^2+6(44)-22

0=-242+264-22

0=-242+242

0=0

5 0

4 years ago

Read 2 more answers

Let f(x)=2/x-3. Find f^-1(x)

KonstantinChe [14]

Answer:

Two questions:

Question 1: $f^{-1}(x)=?$ given $f(x)=\frac{2}{x}-3$ .

Answer 1: $f^{-1}(x)=\frac{2}{x+3}$

Question 2: $f^{-1}(x)=?$ given $f(x)=\frac{2}{x-3}$ .

Answer 2: $f^{-1}(x)=\frac{2}{x}+3$

Step-by-step explanation:

So $f^{-1}$ is used in most classes to represent the inverse function of $f$ .

The inverse when graphed is a reflection through the y=x line. The ordered pairs $(a,b)$ on $f$ implies $(b,a)$ are on $f^{-1}$ .

This means we really just need to swap x and y.

Since we want to write as a function of x we will need to solve for y again.

Question 1:

$y=\frac{2}{x}-3$

Swap x and y:

$x=\frac{2}{y}-3$

We want to solve for y.

Add 3 on both sides:

$x+3=\frac{2}{y}$

Make the left hand side a fraction so we can cross-multiply:

$\frac{x+3}{1}=\frac{2}{y}$

Cross multiply:

$y(x+3)=1(2)$

Simplify right hand side:

$y(x+3)=2$

Divide both sides by (x+3):

$y=\frac{2}{x+3}$

So $f^{-1}(x)=\frac{2}{x+3}$ .

Question 2:

$y=\frac{2}{x-3}$

Swap x and y:

$x=\frac{2}{y-3}$

Make left hand side a fraction so we can cross multiply:

$\frac{x}{1}=\frac{2}{y-3}$

Cross multiply:

$(y-3)x=1(2)$

We have to distribute here:

$yx-3x=2$

Add 3x on both sides:

$yx=2+3x$

Divide boht sides by x:

$y=\frac{2+3x}{x}$

You could probably stop here but you could also simplify a little.

Separate the fraction into two terms since you have 2 terms on top bottom being dividing by x:

$y=\frac{2}{x}+\frac{3x}{x}$

Simplify second fraction x/x=1:

$y=\frac{2}{x}+3$

So $f^{-1}(x)=\frac{2}{x}+3$ .

7 0

3 years ago

Help me. I need help

Gnoma [55]

First blank is 'left'

Second Blank is 'right'

4 0

2 years ago

Family drinks 1 3/4 gallons of milk every 4 1/2 days what is the unit rate of milk per day

natita [175]

$\bf \cfrac{milk}{day}\qquad \cfrac{1\frac{3}{4}}{4\frac{1}{2}}\implies \cfrac{\frac{1\cdot 4+3}{4}}{\frac{4\cdot 2+1}2}\implies \cfrac{\quad \frac{7}{4}\quad }{\frac{9}{2}}\implies \cfrac{7}{\underline{4}}\cdot \cfrac{\underline{2}}{9}\implies \cfrac{7}{2}\cdot \cfrac{1}{9}\implies \cfrac{7}{18}$

which gives us a quotient of about 0.39 gallons of milk for one day.<span />

3 0

4 years ago

Anyone can help me with this?

TEA [102]

one solution x = 0

it is 2- 16x = 2 - 16x

3 0

3 years ago