Step-by-step explanation:
Vamos simplificar passo a passo.
k2-6k4-(3k4+k2+2)
Distribua o sinal negativo:
=k2-6k4+-1(3k4+k2+2)
=k2+-6k4+-1(3k4)+-1k2+(-1)(2)
=k2+-6k4+-3k4+-k2+-2
Combine os termos semelhantes:
=k2+-6k4+-3k4+-k2+-2
=(-6k4+-3k4)+(k2+-k2)+(-2)
=-9k4+-2
Responda:
=-9k4-2
Answer:
a) 2.5 shots
b) 59.4 shots
c) 4.87 shots
Step-by-step explanation:
Probability of making the shot = 0.6
Probability of missing the shot = 0.4
a) The expected number of shots until the player misses is given by:

The expected number of shots until the first miss is 2.5
b) The expected number of shots made in 99 attempts is:

He is expected to make 59.4 shots
c) Let "p" be the proportion shots that the player make, the standard deviation for n = 99 shots is:

The standard deviation is 4.87 shots.
Answer:
The probability that the candidate score is 600 or greater
P(X≥ 600 ) = 0.0228
Step-by-step explanation:
<u><em>Step(i)</em></u>:-
Given mean of the Population = 500
Given standard deviation of the Population = 50
Let 'X' be the random variable in normal distribution
Given X = 600

<u><em>Step(ii)</em></u>:-
The probability that the candidate score is 600 or greater
P(X≥ 600 ) = P(z≥2)
= 0.5 - A(2)
= 0.5 -0.4772
= 0.0228
<u><em>Final answer</em></u>:-
The probability that the candidate score is 600 or greater
P(X≥ 600 ) = 0.0228
Answer:
Rounded Answer: 0
Not Rounded Answer: -0.00198019802
Step-by-step explanation:
Rounded Answer:
20/101 = 0.19801980198
Round that to 0.2
20/99 = 0.2
0.2-0.2 = 0
Not Rounded Answer:
20/101 = 0.19801980198
20/99 = 0.2
Answer: -0.00198019802