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Scorpion4ik [409]
2 years ago
6

Ashley's chocolate bar is 58% cocoa. If the weight of the chocolate bar is 57 grams, how many grams of cocoa does it contain? Ro

und your answer to the nearest tenth.
Mathematics
1 answer:
Thepotemich [5.8K]2 years ago
6 0

Answer:

33.1 grams

Step-by-step explanation:

You know that 58% of the chocolate bar is cocoa and it weighs 57 grams. All you have to do is multiply 0.58 and 57 together. This will give you the amount of grams of cocoa!

58% = 0.58

0.58*57 grams = 33.06

Round up! 33.06 --> 33.1 grams

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(k^2-6k^4)-(3k^4+k^2+2)
jeka57 [31]

Step-by-step explanation:

Vamos simplificar passo a passo.

k2-6k4-(3k4+k2+2)

Distribua o sinal negativo:

=k2-6k4+-1(3k4+k2+2)

=k2+-6k4+-1(3k4)+-1k2+(-1)(2)

=k2+-6k4+-3k4+-k2+-2

Combine os termos semelhantes:

=k2+-6k4+-3k4+-k2+-2

=(-6k4+-3k4)+(k2+-k2)+(-2)

=-9k4+-2

Responda:

=-9k4-2

7 0
3 years ago
A basketball player has made 6060​% of his foul shots during the season. Assume the shots are independent. ​
motikmotik

Answer:

a) 2.5 shots

b) 59.4 shots

c) 4.87 shots

Step-by-step explanation:

Probability of making the shot = 0.6

Probability of missing the shot = 0.4

a) The expected number of shots until the player misses is given by:

E(X) = \frac{1}{P(X)}=\frac{1}{0.4}  \\E(X) = 2.5\ shots

The expected number of shots until the first miss is 2.5

b) The expected number of shots made in 99 attempts is:

E=99*0.6\\E=59.4\ shots

He is expected to make 59.4 shots

c) Let "p" be the proportion shots that the player make, the standard deviation for n = 99 shots is:

s=\sqrt{n*p*(1-p)}\\ s= 4.87\ shots

The standard deviation is 4.87 shots.

7 0
3 years ago
A manufacturing firm tests job applicants. Test scores are normally distributed with a mean of 500 and a standard deviation of 5
Blababa [14]

Answer:

The probability that the candidate score is 600 or greater

P(X≥ 600 ) = 0.0228

Step-by-step explanation:

<u><em>Step(i)</em></u>:-

Given mean of the Population = 500

Given standard deviation of the Population = 50

Let 'X' be the random variable in normal distribution

Given  X = 600

Z = \frac{x-mean}{S.D} = \frac{600-500}{50} = \frac{100}{50} =2

<u><em>Step(ii)</em></u>:-

The probability that the candidate score is 600 or greater

P(X≥ 600 ) = P(z≥2)

                  = 0.5 - A(2)

                 = 0.5 -0.4772

                = 0.0228

<u><em>Final answer</em></u>:-

The probability that the candidate score is 600 or greater

P(X≥ 600 ) = 0.0228

5 0
2 years ago
You bought a car for $20,000. You have owned it for one year, and it is now worth $16,000. What is the percent decrease in your
Ganezh [65]
I think it'd be 20%.. I could be wrong. 
7 0
3 years ago
Read 2 more answers
A) Evaluate 20/101 - 20/99. Express your answer in simplest form.
gulaghasi [49]

Answer:

Rounded Answer: 0

Not Rounded Answer: -0.00198019802

Step-by-step explanation:

Rounded Answer:

20/101 = 0.19801980198

Round that to 0.2

20/99 = 0.2

0.2-0.2 = 0

Not Rounded Answer:

20/101 = 0.19801980198

20/99 = 0.2

Answer: -0.00198019802

3 0
2 years ago
Read 2 more answers
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