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Lerok [7]
3 years ago
11

3=c/5+2... how do I solve for c??

Mathematics
2 answers:
sveticcg [70]3 years ago
6 0
3 = c/5 + 2
3 - 2 = c/5
1 = c/5....multiply both sides by 5, causing the 5 on the right to cancel
5 = c
expeople1 [14]3 years ago
4 0
Primeiro Você IRA Dividir o c (APENAS Colocar 5 + 2 embaixo do c). Depois faça a soma 5 + 2 = 7. Então faça o mmc (mínimo múltiplo comum) entre 7 e 1(o 1 é invisível, mas continua estando embaixo do 3). Deu 7 o mmc. Transforme seus números em frações, com o denominador 7. Transforme os números em frações o 3 virá 21, pois você divide em baixo e multiplica em baixo, e o c continua normal, pois já estava em baixo de 7. Como é para descobrir uma incógnita você tira os denominadores e ficará 21 = c.

3 = c/5 + 2
3 = c/7
21/7 = c/7
21 = c
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