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Lerok [7]
3 years ago
11

3=c/5+2... how do I solve for c??

Mathematics
2 answers:
sveticcg [70]3 years ago
6 0
3 = c/5 + 2
3 - 2 = c/5
1 = c/5....multiply both sides by 5, causing the 5 on the right to cancel
5 = c
expeople1 [14]3 years ago
4 0
Primeiro Você IRA Dividir o c (APENAS Colocar 5 + 2 embaixo do c). Depois faça a soma 5 + 2 = 7. Então faça o mmc (mínimo múltiplo comum) entre 7 e 1(o 1 é invisível, mas continua estando embaixo do 3). Deu 7 o mmc. Transforme seus números em frações, com o denominador 7. Transforme os números em frações o 3 virá 21, pois você divide em baixo e multiplica em baixo, e o c continua normal, pois já estava em baixo de 7. Como é para descobrir uma incógnita você tira os denominadores e ficará 21 = c.

3 = c/5 + 2
3 = c/7
21/7 = c/7
21 = c
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2 years ago
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umka2103 [35]
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5 0
3 years ago
Many universities and colleges have instituted supplemental instruction (SI) programs, in which a student facilitator meets regu
aev [14]

Answer:

Step-by-step explanation:

Let many universities and colleges have conducted supplemental instruction(SI) programs. In that a student facilitator he meets the students group regularly who are enrolled in the course to promote discussion of course material and enhance subject mastery.

Here the students in a large statistics group are classified into two groups:

1). Control group: This group will not participate in SI and

2). Treatment group: This group will participate in SI.

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2 years ago
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kykrilka [37]

Answer:

See solution below

Step-by-step explanation:

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<em>Note that the coordinates are assumed but the same calculation can be employed for any other coordinates</em>

7 0
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