She walks 6/5 of a mile in 1 hour
So, she walks 1.2 miles per hour
Answer:
Natural numbers (integers greater than zero)
X = 3, 5, 4, 4, 3
Step-by-step explanation:
The least number of cars that can be observed in this experiment is 1, if the first car turns left. On the other hand, the experiment could go on forever if no car ever turns left, thus the highest number of cars approaches infinite.
The possible values of X are integers greater than zero, which are known as the Natural numbers.
If X = number of cars observed, simply count the number of letters in each outcome for the value of X:
Outcome = RRL, AARRL, AARL, RRAL, ARL
X = 3, 5, 4, 4, 3
It’s just 5 you divide 9 into 45 and get a whole number of 5
Step-by-step explanation:
I suppose you mean find the range for the following domain. Because when
g(x) is given the value of X
we are trying to solve the output value which is range.
If you want to solve for the domain, the question should give
g(x) = y
and provide the value of y.
X³+X²-X-2
Substitute
X=(-1)
-1+1-(-1)-2
= -1
g(-1)= -1
Substitute
X=(2)
8+4-2-2
=8
g(2)= 8
Substitute
X=(1)
1+1-1-2
=-1
g(1)= -1
g(2)+g(1)
=8-1
=7
Well, we could try adding up odd numbers, and look to see when we reach 400. But I'm hoping to find an easier way.
First of all ... I'm not sure this will help, but let's stop and notice it anyway ...
An odd number of odd numbers (like 1, 3, 5) add up to an odd number, but
an even number of odd numbers (like 1,3,5,7) add up to an even number.
So if the sum is going to be exactly 400, then there will have to be an even
number of items in the set.
Now, let's put down an even number of odd numbers to work with,and see
what we can notice about them:
1, 3, 5, 7, 9, 11, 13, 15 .
Number of items in the set . . . 8
Sum of all the items in the set . . . 64
Hmmm. That's interesting. 64 happens to be the square of 8 .
Do you think that might be all there is to it ?
Let's check it out:
Even-numbered lists of odd numbers:
1, 3 Items = 2, Sum = 4
1, 3, 5, 7 Items = 4, Sum = 16
1, 3, 5, 7, 9, 11 Items = 6, Sum = 36
1, 3, 5, 7, 9, 11, 13, 15 . . Items = 8, Sum = 64 .
Amazing ! The sum is always the square of the number of items in the set !
For a sum of 400 ... which just happens to be the square of 20,
we just need the <em><u>first 20 consecutive odd numbers</u></em>.
I slogged through it on my calculator, and it's true.
I never knew this before. It seems to be something valuable
to keep in my tool-box (and cherish always).
