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Troyanec [42]
3 years ago
14

Jessica is comparing her bank statement to her check register, and the ending balances don't seem to match. To check her registe

r for transposing errors, she needs to subtract the balances and _____ the difference _____.
Mathematics
2 answers:
uranmaximum [27]3 years ago
7 0

Answer:

Divide by 9

Step-by-step explanation:

Lina20 [59]3 years ago
6 0
<span>To balance her check register, Jessica needs to subtract the balances from her bank statement and then add the difference to the ending value of her check register. If entries in her bank statement do not appear in her check register, or vice versa, these transactions need to be tallied and then the added or subtracted from the ending balance in her check register.</span>
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24 POINTS!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!
scoundrel [369]
First, find your total sales. You do this by adding all the sales together, 2030+1540+1800=5370. Now, for each person, divide their sales by total sales.
Lola) 2030/5370=203/537≈0.378=37.8%
Ahmed) 1540/5370=154/537≈0.287=28.7%
Tommy) 1800/5370=180/537=60/179≈0.335=33.5%
5 0
3 years ago
There are 30 chocolates in a box, all identically shaped. There are 11 filled with nuts, 10 with caramel and 9 are solid chocola
igomit [66]

Answer:

I think the answer is 4 1/2 out of 30 chance.

Step-by-step explanation:

3 0
3 years ago
ASAP BRAINLIST . Answer question in the picture
MakcuM [25]

Answer:

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Step-by-step explanation:

3 0
3 years ago
Consider the function on the interval (0, 2π). f(x) = 7 sin2(x) + 7 sin(x) (a) Find the open interval(s) on which the function i
-BARSIC- [3]

Answer with Step-by-step explanation:

Given

f(x)=7sin(2x)+7sin(x)

Differentiating both sides by 'x' we get

14cos(2x)+7cos(x)=f'(x)

Now we know that for an increasing function we have

f'(x)>0\\\\14cos(2x)+7cos(x)>0\\\\2cos(2x)+cos(x)>0\\\\2(2cos^{2}(x)-1)+cos(x)>0\\\\4cos^{2}(x)+cos(x)-2>0\\\\(2cos(x)+\frac{1}{2})^2-2-\frac{1}{4}>0\\\\(2cos(x)+\frac{1}{2})^2>\frac{9}{4}\\\\2cos(x)>\frac{3}{2}-\frac{1}{2}\\\\\therefore cos(x)>\frac{1}{4}\\\\\therefore x=[0,cos^{-1}(1/4)]\cup [2\pi-cos^{-1}(1/4),2\pi ]

Similarly for decreasing function we have

[tex]f'(x)

Part b)

To find the extreme points we equate the derivative with 0

f'(x)=0\\\\cos(x)=\frac{1}{4}\\\\x=cos^{-1}(\frac{1}{4})

Thus point of extrema is only 1.

4 0
4 years ago
A couple finds that they are experiencing debt problems and decide to find a credit counseling agency. What are three (3) things
Serggg [28]

Answer:

This is an odd question...

The couple should find out the following:

1.) is the agency legitimate?

2.) Will they be doing a hard inquiry on our credit history? if so, this could affect our current credit score

3.) Will they charge me to review my current credit reports?

8 0
3 years ago
Read 2 more answers
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