<img src="https://tex.z-dn.net/?f=%20%5Cfrac%7B3%7D%7B2%7D%20x%20-%20%20%5Cfrac%7B3%7D%7B4%7D%20x%20%3D%206" id="TexFormula1" ti

All categories

3 years ago

tle=" \frac{3}{2} x - \frac{3}{4} x = 6" alt=" \frac{3}{2} x - \frac{3}{4} x = 6" align="absmiddle" class="latex-formula">

Mathematics

1 answer:

MAVERICK [17]3 years ago

3 0

$\frac{3}{2}x-\frac{3}{4}x=6$

$\frac{3}{2}x*4-\frac{3}{4}x*4=6*4$

$6x-3x=24$

$3x=24$

$\frac{3x}{3}=\frac{24}{3}$

$x=8$

"x=8 is correct answer."

Hope this helps!

Thanks!

-Charlie

You might be interested in

QUESTION 1 Name the type of transformation depicted by the picture. reflection rotation translation none of the above

nydimaria [60]

I would be happy to help but it seems there are no pictures attached to answer from.

7 0

2 years ago

Which equation is the inverse of 5 y + 4 = (x + 3) squared + one-half?

telo118 [61]

Answer:

The correct option is the last option d.) y = negative 3 plus-or-minus StartRoot 5 x + seven-halves EndRoot

Step-by-step explanation:

the given equation is $5y + 4 =(x+3)^{2} + \frac{1}{2}$

Therefore we can write $5y\hspace{0.1cm} = (x+3)^{2} + \frac{1}{2} - 4 \hspace{0.3cm} \Rightarrow \hspace{0.2cm} 5y = (x+3)^{2} - \frac{7}{2} \hspace{0.3cm} \Rightarrow \hspace{0.3cm} y = \frac{(x+3)^{2}}{5} - \frac{7}{10}$

To find the inverse of the above function let us replace x with y and y with x.

Therefore we get

$x = \frac{(y+3)^{2}}{5} - \frac{7}{10}$

Now we write the above equation with only y on the Left hand side and we will obtain the inverse of the given function

$y = \pm \sqrt{5 (x + \frac{7}{10} )} \hspace{0.1cm} - \hspace{0.1cm} 3 \hspace{0.1cm} \Rightarrow\hspace{0.1cm} y = \pm \sqrt{5x + \frac{7}{2} } - \hspace{0.1cm} 3 \hspace{0.1cm}$

Therefore the correct option is the last option d.) y = negative 3 plus-or-minus StartRoot 5 x + seven-halves EndRoot , $y = \pm \sqrt{5x + \frac{7}{2} } - \hspace{0.1cm} 3 \hspace{0.1cm}$