Question

Students of a large university spend an average of $5 a day on lunch. The standard deviation of the expenditure is $3. A simple random sample of 36 students is taken. a) What is the expected value, standard deviation, and shape of the sampling distribution of the sample mean

Answer 1

Answer and Step-by-step explanation:

According to the situation the solution is shown below:-

The expected value is

$\mu = 5$

The standard deviation is

= $3

The sample distribution of the sample standard deviation is

$\sigma_x = \frac{\sigma}{\sqrt{n} } \\\\ = \frac{3}{\sqrt{36} } \\\\ = \frac{3}{6}$

After solving the above equation  we will get

= 0.5

Basically we applied the applied formula so that each part could be determined