Question

Plz help me idk what t0o do

Answer 1

Answer:

$y = - \frac{1}{2} x + 2$

Step-by-step explanation:

According to the chart for the values of x (input) the corresponding values of y (output) are given.

The slope of the equation is constant and given by $m = - \frac{1}{2}$.

If we want to check the slope to be constant then we can use the table and the values of x and y.

The first point ($x_{1},y_{1}$) ≡ (-2,3)

The second point ($x_{2},y_{2}$) ≡ (8,-2)

The third point ($x_{3},y_{3}$) ≡ (10,-3)

The fourth point ($x_{4},y_{4}$) ≡ (20,-8)

Now, we can check that slope of the straight line is constant for all those values.

$\frac{y_{2} - y_{1}}{x_{2} - x_{1}} = \frac{- 2 - 3}{8 - (- 2)} = - \frac{1}{2}$

$\frac{y_{3} - y_{2}}{x_{3} - x_{2}} = \frac{- 3 - (- 2)}{10 - 8} = - \frac{1}{2}$

$\frac{y_{4} - y_{3}}{x_{4} - x_{3}} = \frac{- 8 - (- 3)}{20 - 10} = - \frac{1}{2}$

Now, Let us assume that the equation of the straight line is $y = - \frac{1}{2} x + c$ ....... (1)

Now, we have to find the value of c.

This straight line passes through ($x_{1},y_{1}$) ≡ (-2,3) point.

So, the value of c can be calculated from the equation (1) as, c = 3 - 1 = 2

Therefore, $y = - \frac{1}{2} x + 2$ is the required equation. (Answer)