First, list all the given information:
*100 miles/week
*25 miles/gallon
*$4/gallon
*weekly expenditure reduced by $5
The easiest approach to use here is the dimensional analysis. Cancel out like units if they appear both in the numerator and denominator side. Solve first the original cost. The solution is as follows:
100 miles/week * 1 gal/25 miles * $4/gal = $16/week
The reduced cost would be:
16 - 5 = (New average miles/week) * 1 gal/25 miles * $4/gal
New average miles/week = 68.75 miles/week
1. Pick two points on the line and determine their coordinates.
2. Determine the difference in y-coordinates of these two points (rise).
3. Determine the difference in x-coordinates for these two points (run).
4. Divide the difference in y-coordinates by the difference in x-coordinates (rise/run or slope).
3x - 2 = 13
Add 2 on both sides
3x - 2 + 2 = 13 + 2
3x = 13 + 2
3x = 15
Divide both sides by 3.
3x/3 = 15/3
x = 15/3
x = 5
Your final answer is A. 5.
Answer:
See explanation
Step-by-step explanation:
Factorize numbers 42 and 56:

These two numbers have common factors 2 and 7. So,
A. Mr. Ellis can divide the group into
- 1 team = 42 ten-year-olds and 56 nine-year-olds (actually this is not dividing only completing 1 team);
- 2 teams = 21 ten=year-olds and 28 nine-year-olds in each team;
- 7 teams = 6 ten-year-olds and 8 nine-year-olds in each team;
- 14 teams = 3 ten-year-olds and 4 nine-year-olds in each team.
So, there are 3 different ways to divide the group of students into teams.
B. The greatest number of teams Mr. Ellis can make so each team has the same number of 9-year-olds and the same number of 10-year-olds is 14 teams.
C. If Mr. Ellis gives a snack to each winner, then he is interested to give the smallest number of snacks, the smallest number of snacks will be when the number of students in the team is the smallest, the smallest number of students will be when the greatest number of teams are created.