Each pant cost $13.50 because 71-17=54 and 54/4=13.5. Julie has 17 apples.
Answer:
A = π/6 + kπ, or A = 2π/3 + kπ
Step-by-step explanation:
tan A / (1 − tan² A) = √3 / 2
Cross multiply and simplify:
√3 (1 − tan² A) = 2 tan A
√3 − √3 tan² A = 2 tan A
3 − 3 tan² A = 2√3 tan A
0 = 3 tan² A + 2√3 tan A − 3
Solve with quadratic formula:
tan A = [ -2√3 ± √((2√3)² − 4(3)(-3)) ] / 2(3)
tan A = [ -2√3 ± √(12 + 36) ] / 6
tan A = (-2√3 ± √48) / 6
tan A = (-2√3 ± 4√3) / 6
tan A = -√3 or √3/3
Solve for A:
A = 2π/3 + kπ, or A = π/6 + kπ
Answer: You apply the trigonometric ratios of Sine, Cosine and Tangent.
Step-by-step explanation: In a question such as this one of the angles must be given, which is labeled the reference angle. We already know one angle is 90 degrees in a right angled triangle, so the other two angles whatever their size is, must both add up to 90, which means they are both acute angles. If one side is given, for instance 10 units, and one of the two acute angles is given, for example 30 degrees, then the line facing the reference angle (30 degrees) would be the OPPOSITE. The line that lies between the angles 30 and 90 would be the ADJACENT while the third side which is the longest would be the HYPOTENUSE.
So if for instance, the opposite line is 10 units, and you are required to calculate the other line, the adjacent, AS LONG AS YOU HAVE BEEN GIVEN A REFERENCE ANGLE, you can simply calculate as follows;
TanX = opposite/adjacent (and that becomes)
Tan 30 = 10/adj
Adj = 10/Tan 30
Adj = 10/0.5774
Adj = 17.32
**Note that the use of angle 30 was just for the sake of explanation. Your reference angle whatever it is, would be provided by your examiner**
Answer:
<h2>742</h2>
Step-by-step explanation:
Answer:
the smiths family has 2 choices to make , color and style, By the fundamental counting principle, the product of the number of choices of color and style must equal 8. So, there could be 1 color and 8 style choices .2 colors and 4 styles ,4 colors and 2 styles , or 8 colors and 1 style.
Step-by-step explanation:
I just answered the question