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DiKsa [7]
3 years ago
7

Which of the following is equivalent to sin theta csc(–theta) wherever sin theta csc(–theta) is defined?

Mathematics
1 answer:
Firlakuza [10]3 years ago
3 0
sin\theta csc(-\theta)=sin\theta\cdot\frac{1}{sin(-\theta)}=sin\theta\cdot\frac{1}{-sin\theta}=\frac{1}{-1}=-1\\\\Answer:F
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Find the value of x so that the polygons have the same perimeter
mestny [16]

x - 2  + x + 4 + x - 2  + 4 - 4 = x + 3 + x + 4 + x + 5

4x + 4 = 3x + 12

4x - 3x = 12 - 4

x = 8

6 0
3 years ago
Elizabeth drove two-fifths of a mile in 30 seconds. Which of the following shows
hichkok12 [17]

Answer:

c.

Step-by-step explanation:

4 0
2 years ago
A garden is shaped in the form of a regular heptagon (seven-sided), MNSRQPO. A circle with center T and radius 25m circumscribes
Alenkinab [10]

The relationship between the sides MN, MS, and MQ in the given regular heptagon is \dfrac{1}{MN} = \dfrac{1}{MS} + \dfrac{1}{MQ}

The area to be planted with flowers is approximately <u>923.558 m²</u>

The reason the above value is correct is as follows;

The known parameters of the garden are;

The radius of the circle that circumscribes the heptagon, r = 25 m

The area left for the children playground = ΔMSQ

Required;

The area of the garden planted with flowers

Solution:

The area of an heptagon, is;

A = \dfrac{7}{4} \cdot a^2 \cdot  cot \left (\dfrac{180 ^{\circ}}{7} \right )

The interior angle of an heptagon = 128.571°

The length of a side, S, is given as follows;

\dfrac{s}{sin(180 - 128.571)} = \dfrac{25}{sin \left(\dfrac{128.571}{2} \right)}

s = \dfrac{25}{sin \left(\dfrac{128.571}{2} \right)} \times sin(180 - 128.571) \approx 21.69

The \ apothem \ a = 25 \times sin \left ( \dfrac{128.571}{2} \right) \approx 22.52

The area of the heptagon MNSRQPO is therefore;

A = \dfrac{7}{4} \times 22.52^2 \times cot \left (\dfrac{180 ^{\circ}}{7} \right ) \approx 1,842.94

MS = \sqrt{(21.69^2 + 21.69^2 - 2 \times  21.69 \times21.69\times cos(128.571^{\circ})) \approx 43.08

By sine rule, we have

\dfrac{21.69}{sin(\angle NSM)} = \dfrac{43.08}{sin(128.571 ^{\circ})}

sin(\angle NSM) =\dfrac{21.69}{43.08} \times sin(128.571 ^{\circ})

\angle NSM = arcsin \left(\dfrac{21.69}{43.08} \times sin(128.571 ^{\circ}) \right) \approx 23.18^{\circ}

∠MSQ = 128.571 - 2*23.18 = 82.211

The area of triangle, MSQ, is given as follows;

Area \ of \Delta MSQ = \dfrac{1}{2}  \times  43.08^2 \times sin(82.211^{\circ}) \approx 919.382^{\circ}

The area of the of the garden plated with flowers, A_{req}, is given as follows;

A_{req} = Area of heptagon MNSRQPO - Area of triangle ΔMSQ

Therefore;

A_{req}= 1,842.94 - 919.382 ≈ 923.558

The area of the of the garden plated with flowers, A_{req} ≈ <u>923.558 m²</u>

Learn more about figures circumscribed by a circle here:

brainly.com/question/16478185

6 0
3 years ago
Solve the inequality and graph the solution |7x-7|+2&lt;23
Naya [18.7K]

|7x-7|+2 < 23\ \ \ \ \ |-2\\\\|7x-7| < 21\iff7x-7 < 21\ \wedge\ 7x+7 > -21\ \ \ \ \ \ |+7\\\\7x < 28\ \wedge\ 7x > -14\ \ \ \ \ \ \ |:7\\\\x < 4\ \wedge\ x > -2\\\\-2 < x < 4

3 0
3 years ago
12.22 divided by 5.62
katen-ka-za [31]
2.174377...
About 2.17
8 0
3 years ago
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