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tatiyna
2 years ago
9

Find the residual values, and use the graphing calculator tool to make a residual plot. A 4-column table with 5 rows. The first

column is labeled x with entries 1, 2, 3, 4, 5. The second column is labeled given with entries negative 3.5, negative 2.9, negative 1.1, 2.2, 3.4. The third column is labeled predicted with entries negative 1.1, 2, 5.1, 8.2, 1.3. The fourth column is labeled residual value with all entries blank. Does the residual plot show that the line of best fit is appropriate for the data? Yes, the points have no pattern. No, the points are evenly distributed about the x-axis. No, the points are in a linear pattern. Yes, the points are in a curved pattern.
Mathematics
1 answer:
Svetlanka [38]2 years ago
5 0

The best answer from the options that proves that the residual plot shows that the line of best fit is appropriate for the data is: ( Statement 1 ) Yes, because the points have no clear pattern

X         Given     Predicted     Residual value

1            3.5           4.06             -0.56

2           2.3           2.09             0.21

3            1.1            0.12               0.98

4           2.2           -1.85              4.05

5          -4.1            -3.82            -0.28

The residual value is calculated as follows using this formula: ( Given - predicted )

1) ( 3.5 - 4.06 ) = -0.56

2) ( 2.3 - 2.09 ) = 0.21

3) ( 1.1 - 0.12 ) = 0.98

4) (2.2 - (-1.85) = 4.05

5) ( -4.1 - (-3.82) = -0.28

Residual values are the difference between the given values and the predicted values in a given data set and the residual plot is used to represent these values .

attached below is the residual plot of the data set

hence we can conclude from the residual plot attached below that the line of best fit is appropriate for the data because the points have no clear pattern ( i.e. scattered )

learn more about residual plots : brainly.com/question/16821224

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C. \frac{1}{18}

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Let B be the event when one of the two cards is 5

probability than one of two cards is 5 when sum of cards is 8

p(\frac{\text{B}}{\text{A}})=\frac{\text{total case when one of the number is 5}}{\text{total case when sum is 8}}

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p(\text{A and B})=\frac{5}{36}\times\frac{2}{5}

p(\text{A and B})=\frac{1}{18}

if sum of cards is 8 then probability that one of the cards is 8 is \frac{1}{18}, option C is correct.

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